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Aleks04 [339]
2 years ago
14

What is 90 divided by 19 +607 divided by 1

Mathematics
1 answer:
fredd [130]2 years ago
6 0

Answer:

611.73

Step-by-step explanation:

90 divided by 19 is 4.73 then add 607 which adds up to 611.73 then divide by 1 which is 611.73

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Plz plz plz plz help me​
Mrac [35]

Answer:

Solution given:

perpendicular [P]=15m

base[B]=8m

hypotenuse [H]=17m

rate :4 plants per square metre

no of plants=?

we have

Area of triangular garden: ½(P*B)=½(15*8)=60m²

Now

Total no of plants =rate ×Area =4×60=240

Michael needs <u>240</u> plants in the garden

3 0
3 years ago
Can you help me find X please.​
Mashcka [7]
The answer is 5 I’m not sure if this is correct
4 0
3 years ago
What is the answer to this word problem or how would I solve it
USPshnik [31]
Its a simultaneous equation:
lets make "x" the used games and "y" the new ones

4x + 2y = 84
6x + y = 78. (multiply this by 2 to cancel out y)
12x + 2y = 156

so now we subtract them:
12x - 4x = 156 - 84
x = 9
used games cost $9
new games cost 78 - 6(9) = $24

Janet has $120 but she already bought 3 NEW games so:
120 - 3(24) = $48 left

48/9 = how many used ones she can buy = 5. something

she can buy 5 used
5 0
3 years ago
In an election, Candidate A received 75 votes and candidate B received 25 votes, after the first 100 votes were counted. Assume
enot [183]

Answer:

Candidate receives 2250 votes

Step-by-step explanation:

Ratio of votes A : B = 75 : 25  = 3 : 1

3 : 1 = x : 750

Product of means = Product of extremes

1 *x = 3*750

  x = 3 *750

     = 2250

3 0
2 years ago
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

  • The common ratio is: \mathbf{r = \frac{a + 5d}{a + d}}
  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
3 years ago
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