You would do:
t = time in years
14,800 = 10,000(1+0.08/4)^4t
1.48 = 1.02^4t
log_1.02(1.48) / 4 = t
((log 1.48)/ (log 1.02))/4 = t
t ~ 4,949 years
Answer:
Tenicai had the greatest prectnt errou
Step-by-step explanation:
The two equations are equivalent.
The postage for 3 posters is $5.
Lois$ wrote an expression for the total they both spent as 6x + 10 6(25) +10
150 +10 = 160
Clark wrote another expression for the total, saying that it represented the same cost: 2(3x + 5). = 2(3x) + 2(5) 6x + 10 = 6(25) + 10 = 150+10 160
If each poster costs $25, do the two expressions give the same amount?
Answer:
17
Step-by-step explanation:
3(4)+5
12+5
17