Answer:
z³ = 64
z³=4³
since power is equal, base will be same
z=4
Step-by-step explanation:
Answer:
Step-by-step explanation:
WITHOUT replacement of first card drawn:
P(a 10 is drawn) = 13/52 = 1/4
P(the next draw is a 10) = 12/52 = 3/13
P(drawing two 10s without replacement of the first draw) = (1/4)(3/13) = 3/52
WITH replacement of first card:
P(two 10s are drawn) = P(first card is a 10)*P(first card is a 10) = (4/13)(4/13) =
16/169
Answer:
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Step-by-step explanation: sorry lol
Answer:
Mean. It includes all data points.
Step-by-step explanation:
-We first need to calculate the mean, median and mode then compare our values:
#Mean:
#The median is the middlemost data point in a lsit data:
778,783,784,786,790,804,807,810,819,823
-Since our data points is an even number, the median number is calculated as:
![median=\frac{1}2}\sum{5^{th}+6^{th}}\\\\=0.5[790+804]\\\\=797.00](https://tex.z-dn.net/?f=median%3D%5Cfrac%7B1%7D2%7D%5Csum%7B5%5E%7Bth%7D%2B6%5E%7Bth%7D%7D%5C%5C%5C%5C%3D0.5%5B790%2B804%5D%5C%5C%5C%5C%3D797.00)
#Mode is the data point with the highest frequency:
-Since there's no number appearing more than once, our set has no mode.
#Since our data set has no outliers and is not a skewed distribution, the mean will be the best measure as it includes all data points
48 = 48 * 1 = 24 * 2 = 16 * 3 = 12 * 4 = 8 * 6
So the factors of 48 are: 1, 2, 3, 4, 6, 89, 12, 16, 24 and 48.
The multiples of 4 are: 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48,...
Answer:
Multiples of 4 that are not factors of 48 are: 20, 28, 32, 36, 40, 44.
