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scZoUnD [109]
3 years ago
5

Question 6 Find the slope of the line passing through the points (11,-5) and (11,6)

Mathematics
1 answer:
zimovet [89]3 years ago
3 0

There are two ways to approach this.

Option #1:

Use the slope formula m = \dfrac{y_2-y_1}{x_2-x_1}.

    m= \dfrac{6-(-5)}{11-11} = \dfrac{11}{0}

That value is undefined, so the slope is undefined.

Option #2:

Because the two points have the same x-value, they will be vertically above/below one another.  This means your line is a vertical line and the slope of a vertical line is undefined.

Either way, your slope is undefined.

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A stem-and-leaf plot is made using the following values. Which does NOT correctly represent a line of stem and leaves from the p
melomori [17]

Answer:

7

Step-by-step explanation:

70, 72, 72, 72, 74, 76

There are 6 numbers that have 7 as a 10. There are only 5 ones on the leaf of the stem 7. The 6 is missing.

5 0
3 years ago
⦁ Find the length of the third angle of a triangle given that the first two angles are 35 and 70. Show your work.
UNO [17]
180 - 70 = 110
110 - 35 = 75
The third angle is 75
3 0
3 years ago
Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

8 0
3 years ago
;-; hehehehehehehehehe
iogann1982 [59]

Answer: hahahahahaha

Step-by-step explanation:

Hahahahaha mines more cringe ;)

8 0
3 years ago
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Please HELP ASAP £ FREE BRAINLIST :)​
Aleksandr [31]

Answer:

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2 ft/s

Step-by-step explanation:

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