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scZoUnD [109]
3 years ago
5

Question 6 Find the slope of the line passing through the points (11,-5) and (11,6)

Mathematics
1 answer:
zimovet [89]3 years ago
3 0

There are two ways to approach this.

Option #1:

Use the slope formula m = \dfrac{y_2-y_1}{x_2-x_1}.

    m= \dfrac{6-(-5)}{11-11} = \dfrac{11}{0}

That value is undefined, so the slope is undefined.

Option #2:

Because the two points have the same x-value, they will be vertically above/below one another.  This means your line is a vertical line and the slope of a vertical line is undefined.

Either way, your slope is undefined.

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Hey there :)

We know the distance formula is:
D = \sqrt{(x2-x1)^2+(y2-y1)^2}

1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
                                    ↓   ↓       ↓    ↓
                                    x₁ y₁     x₂   y₂
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We do the same for the rest

2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
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3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
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4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
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5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D = \sqrt{(-8-6)^2 + (9-(-3))^2}
   ≈ 18.4 (nearest tenth) 

You can find the matching below :)



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Step-by-step explanation:

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