The first way to try to fix this is to apply logarithm to the observations on the dependent variable. This is going to make the dependent variable with high degree of kurtosis normal.
Note that sometimes, the resulting values of the variable will be negative. Do not worry about this, as it is not a problem. It does not affect the regression coefficients, it only affects the regression intercept, which after transformation, will be of no interest.
Answer:
y = -(5/2)x -2
Explanation:
The general formula for a straight line is y – mx + b.
The image below shows the graph of the line.
Step 1. <em>Calculate the slope</em>.
Slope = m = Δy/Δx = (y₂-y₁)/(x₂-x₁)
x₁ = 0; y₁ = -2
x₂ = -2; y₂ = 3 Calculate m
m = [3-(-2)]/(-2-0)
m = (3+2)/(-2)
m = 5/(-2)
m = -5/2
Step 2. <em>Calculate the y-intercept
</em>
When x = 0, y = 2.
The y-intercept (b) is at y = -2
Step 3. <em>Write the equation </em>for the graph
y = mx + b
y = -(5/2)x - 2
Answer:
Given
Step-by-step explanation:
<A and <D are supplementary
Answer:
<h2>D. 3</h2>
Step-by-step explanation:



Mark points in the coordinate system.
Lead a line through these points.
Read x-intercept.
I hope this helps you
244=4.61
2square roof 61