Answer:
Step-by-step explanation:
If base of variable is same, add the powers
1) x² * x * x³ * x⁵ = x²⁺¹⁺³⁺⁵ = x¹¹
2) -2n² * -n⁴ * 5n³ = (-2* -1* 5 ) *n²⁺⁴⁺³ = 10n⁹
3)-3x⁴ * 2x⁵ * - x = (-3 * 2 * -1)* x⁵⁺⁴⁺¹ = 6x¹⁰
Answer: The distance between the girls is 362.8 meters.
Step-by-step explanation:
So we have two triangle rectangles that have a cathetus in common, with a length of 160 meters.
The adjacent angle to this cathetus is 40° for Anna, then the opposite cathetus (the distance between Anna and the tower) can be obtained with the relationship:
Tan(A) = opposite cath/adjacent cath.
Tan(40°) = X/160m
Tan(40°)*160m = 134.3 m
Now, we can do the same thing for Veronica, but in this case the angle adjacent to the tower is 55°
So we have:
Tan(55°) = X/160m
Tan(55°)*160m = X = 228.5 m
And we know that the girls are in opposite sides of the tower, so the distance between the girls is equal to the sum of the distance between each girl and the tower, then the distance between the girls is:
Dist = 228.5m + 134.3m = 362.8m
Answer:
attached below
Step-by-step explanation:
Attached below is a detailed solution to your problem above
a) show that the maximum likelihood estimator of Ï2 is Xi and Yi.
attached below is the detailed solution
The greatest common factor is 1 hope this helps you
The total distance was 35 miles. Why? Well, see below:
The student ran 3 miles each day for 5 days. That can be representative of:
Day 1: 3 miles
Day 2: 3 miles
Day 3: 3 miles
Day 4: 3 miles
Day 5: 3 miles
Adding these values together, we will find that the student ran a total of 15 miles in the first five days.
As for the next set of 5 days, we can represent this by modeling like we did above:
Day 6: 4 miles
Day 7: 4 miles
Day 8: 4 miles
Day 9: 4 miles
Day 10: 4 miles
Adding the values from the second set of days, we will find that in days 6-10, the student ran a total of 20 miles.
We can add the total values together to identify the total distance the student ran during these 10 days.
15 + 20 = 35 total miles
Hence, the student ran a total of 35 miles over the course of 10 days. If you need help, let me know and I will go ally assist you.
