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Dmitriy789 [7]
3 years ago
11

Which of the following is a horizontal stretch of the parent function?

Mathematics
2 answers:
dlinn [17]3 years ago
8 0

Answer:

The correct option is 3.

Step-by-step explanation:

The parent function is

f(x)=|x|

The horizontal stretch and compression is defined as

g(x)=|bx|

If 0<b<1, then it is horizontal stretch and if b>1, then it is horizontal compression.

Graph 1 passing thought the point (1,-1).

-1=|b(1)|

This statement is false for any value of b, because the value of modulus can not be negative.

Graph 2 passing thought the point (1,2).

2=|b(1)|

2=b

Since b>1, therefore this graph represent the horizontal compression.

Graph 3 passing thought the point (2,1).

1=|b(2)|

\frac{1}{2}=b

Since 0<b<1, therefore this graph represent the horizontal stretch.

Thus, the correct option is 3.

melisa1 [442]3 years ago
6 0

Answer:

C.

Step-by-step explanation:

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Identify the number of solutions. Y&lt; -1/3x+5, y&gt; -1/3x-1.
Elenna [48]

Answer: C. No solution. ( top shaded. Middle not. Bottom shaded.


Step-by-step explanation:

Given inequalities

y< -1/3x+5 and

y> -1/3x-1.

If we draw graph for y< -1/3x+5 equation, it would be a dotted line and we would shade down the dotted line because we have less than < symbol there.

Now, if we draw graph for second inequality y> -1/3x-1, it would also be a dotted line and we would shade up of dotted line because we have greater  than > symbol there.

Now, we can see that slopes of both dotted lines are same that is -1/3.

So, there would not be any common shaded region.

Therefore, there would not by any solution of the system of inequalities.

And correct option is C option.

C. No solution. ( top shaded. Middle not. Bottom shaded.

8 0
3 years ago
Can someone help me please? Am I right or no?
Juliette [100K]
The figure consists of three objects, a rectangle, a trapezoid, a triangle

Find the area of the rectangle
The rectangle is 16 in long and 9 in wide
a₁ = l × w
a₁ = 16 × 9
a₁ = 144 in²

Find the area of the trapezoid
The base of trapezoid is 31 in and 16 in, and the height is 35 - 20 = 15 in.
a₂ = 1/2 × (a + b) × h
a₂ = 1/2 × (31 + 16) × 15
a₂ = 1/2 × 47 × 15
a₂ = 352.5 in²

Find the area of the triangle
The base of the triangle is 31 in, the height is 20 in
a₃ = 1/2 × b × h
a₃ = 1/2 × 31 × 20
a₃ = 310 in²

Add the area together
a = a₁ + a₂ + a₃
a = 144 + 352.5 + 310
a = 806.5

The answer is 806.5 in²
4 0
3 years ago
Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund
lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

\sigma=\sqrt{\frac{p*(1-p)}{n} }

If n=1139 and p =0.96, the standard deviation is:

\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836

The minimum and maximum usual values are:

\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n

\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62

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Half a number increased by 15 is equal to the sum of 5 and the product of 3 and the number.
son4ous [18]

Answer:

(x/2) + 15 = 5 + 3x

Step-by-step explanation:

Follow the steps in the equation. X is your number. First you halve it, then you add 15. Next, set it equal to the other side. The second side is 5 + (because it is the sum) and 3x (the product of 3 and x means multiply them)

3 0
3 years ago
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