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3 years ago

Please anyone help I’ll mark you brainliest.

Mathematics

1 answer:

STALIN [3.7K]3 years ago

8 0

Answer:

Sam is correct because when the exponents are in parenthesis, you multiply the exponents

Step-by-step explanation:

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A gardener buys a rake and a pair of gloves for each of the 12 volunteers in the gardening club. Each pair of gloves

matrenka [14]

Let unit cost of one rake be : r

Given : Total number of volunteers = 12

Given : Each pair of gloves cost $8.00

⇒ Cost of 12 pair of gloves for 12 volunteers = (12 × 8) = $96

Given : The gardener spends a total of $300 on both rakes and gloves

⇒ Cost of 12 rakes + Cost of 12 pair of gloves = $300

⇒ 12r + 96 = 300

⇒ 12r = 204

⇒ r = 17

<u>Answer</u> : Cost of one rake is $17

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3 years ago

Monica has 8 more than 3 times the number of marbles Regina has.if Regina has r marbles,how many marbles does Monica have?

jarptica [38.1K]

Monica has +8(3 times (Regina))or

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4 years ago

Corinna has $72. She wants to buy a $281 plane ticket. She will save up her earnings from working at the museum where she earns

kvv77 [185]

Answer:the correct answer is b

Step-by-step explanation:

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4 years ago

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Margarita [4]

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3 years ago

Which expression should you simplify to find the 90% confidence interval,

Alex787 [66]

Answer:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

Step-by-step explanation:

The estimated proportion of interest is $\hat p=0.45$

We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value is:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the true population proportion is interest is given by this formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Replacing the values provided we got:

$0.45 - 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.287$

$0.45 + 1.96\sqrt{\frac{0.45(1-0.45)}{36}}=0.613$

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613

8 0

3 years ago