3 years ago

If a=3, b=-5 fond the value of (2a+3b) (4a sq- 6ab+9b square)

Mathematics

1 answer:

snow_lady [41]3 years ago

4 0

Step-by-step explanation:

(2a+3b)(4a²-6ab+9b²

(2a+3b){(2a)²-2a×3b+(3b)²}

Because (a³+b³)=(a+b)(a²-ab+b²)

Therefore,

(2a+3b){(2a)²-2a×3b+(3b)²}

=(2a)³+(3b)³

By substituting the values , we get

(2a)³+(3b)³
(2×3)³+(3×(-5))³
6³+(-15)³
216+(-3375)
216-3375
-3159

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If a=3, b=-5 fond the value of (2a+3b) (4a sq- 6ab+9b square)​

If a=3, b=-5 fond the value of (2a+3b) (4a sq- 6ab+9b square)