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alukav5142 [94]
3 years ago
15

If a=3, b=-5 fond the value of (2a+3b) (4a sq- 6ab+9b square)​

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0

Step-by-step explanation:

(2a+3b)(4a²-6ab+9b²

(2a+3b){(2a)²-2a×3b+(3b)²}

Because (a³+b³)=(a+b)(a²-ab+b²)

Therefore,

(2a+3b){(2a)²-2a×3b+(3b)²}

=(2a)³+(3b)³

By substituting the values , we get

  • (2a)³+(3b)³
  • (2×3)³+(3×(-5))³
  • 6³+(-15)³
  • 216+(-3375)
  • 216-3375
  • -3159
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A barista averages making 16 coffees per hour. At this rate, how many hours will it take until she’s made 1,200 coffees?
nignag [31]

Answer:

75 hours

Step-by-step explanation:

16 times x=1200 or

16x=1200

divide both sides by 16

1200/16

so we simplify 1200/16 by factoring out the ones (4/8=1/2 times 4/4 since 4/4=1)

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5 0
3 years ago
An insect measured 1.25cm wich numbeer is less than 1.25?<br><br>a)1.35, b)1.3, c)1.26 , d)1.2​
Igoryamba
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2 years ago
One of the vertices of an equilateral triangle is on the vertex of a square and two other vertices are on the not adjacent sides
Elina [12.6K]
<h2>Answer:</h2>

<em> The side of the triangle is either 38.63ft or 10.35ft</em>

<h2>Step-by-step explanation:</h2>

This problem can be translated as an image as shown in the Figure below. We know that:

  • The side of the square is 10 ft.
  • One of the vertices of an equilateral triangle is on the vertex of a square.
  • Two other vertices are on the not adjacent sides of the same square.

Let's call:

Since the given triangle is equilateral, each side measures the same length. So:

x: The side of the equilateral triangle (Triangle 1)

y: A side of another triangle called Triangle 2.

That length is the hypotenuse of other triangle called Triangle 2. Therefore, by Pythagorean theorem:

\mathbf{(1)} \ x^2=100+y^2

We have another triangle, called Triangle 3, and given that the side of the square is 10ft, then it is true that:

y+(10-y)=10

Therefore, for Triangle 3, we have that by Pythagorean theorem:

(10-y)^2+(10-y)^2=x^2 \\ \\ 2(10-y)^2=x^2 \\ \\ \\ \mathbf{(2)} \ x^2=2(10-y)^2

Matching equations (1) and (2):

2(10-y)^2=100+y^2 \\ \\ 2(100-20y+y^2)=100+y^2 \\ \\ 200-40y+2y^2=100+y^2 \\ \\ (2y^2-y^2)-40y+(200-100)=0 \\ \\ y^2-40y+100=0

Using quadratic formula:

y_{1,2}=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ y_{1,2}=\frac{-(-40) \pm \sqrt{(-40)^2-4(1)(100)}}{2(1)} \\ \\ \\ y_{1}=37.32 \\ \\ y_{2}=2.68

Finding x from (1):

x^2=100+y^2 \\ \\ x_{1}=\sqrt{100+37.32^2} \\ \\ x_{1}=38.63ft \\ \\ \\ x_{2}=\sqrt{100+2.68^2} \\ \\ x_{2}=10.35ft

<em>Finally, the side of the triangle is either 38.63ft or 10.35ft</em>

5 0
3 years ago
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