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BigorU [14]
3 years ago
6

How many tenths are in 14.5

Mathematics
1 answer:
Advocard [28]3 years ago
6 0
N/10 = 29/2

n = 290/2

n = 145
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Find the vertices and foci of the hyperbola with equation (x-5)^2/81 -(y-1)^2/144 = 1
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Given the equation of an hyperbola in the form:
\frac{(x-a)^2}{b^2}- \frac{(y-c)^2}{d^2}=1
Then the focus of the hyperbola is (\pm\sqrt {b^2+d^2},0)
Compute like this:
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since \sqrt{81}=9
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