Answer:
The perimeter of triangle PQR is 17 ft
Step-by-step explanation:
Consider the triangles PQR and STU
1. PQ ≅ ST = 4 ft (Given)
2. ∠PQR ≅ ∠STU (Given)
3. QR ≅ TU = 6 ft (Given)
Therefore, the two triangles are congruent by SAS postulate.
Now, from CPCTE, PR = SU. Therefore,
Now, side PR is given by plugging in 3 for 'y'.
PR = 3(3) - 2 = 9 - 2 = 7 ft
Now, perimeter of a triangle PQR is the sum of all of its sides.
Therefore, Perimeter = PQ + QR + PR
= (4 + 6 + 7) ft
= 17 ft
Hence, the perimeter of triangle PQR is 17 ft.
968.58=200.78+76.78w
-200.78
767.8=76.78w
/76.78
=10w
Riley must save for 10 weeks
Any polynomial's graph cannot have two simultaneous maxima, so they must contain a minima between them. Thus, the total number of turning points of the graph is 3. Generally, when plotting a polynomial, the number of turning points is:
n = d -1; where d is the degree of the polynomial and n is the number of turning points. Thus, this function's degree must be at least 4. The answer is b.
Answer:
x=5
Step-by-step explanation:
That is your answer .
First you do 4x-3+3=2x+7+3
then,4x=2x+10,then
subtract 2x from both side
4x-2x=2x+10-2x
simplify
2x=10
divide both sides by 2 2x/2=10/2
simplfy and you get x=5
Hope this helps :)
Answer:
Step-by-step explanation:
rewrite as multiplication
look to factor
, difference of 2 squares and perfect square
, finish factoring and simplify
2(x+3)
