Answer:
They are increasing at the same rate.
The minimum surface area that such a box can have is 380 square
<h3>How to determine the minimum surface area such a box can have?</h3>
Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
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The shorter leg is 21cm, longer leg is 28 cm and hypotenuse is 35cm.
Step-by-step explanation:
Let,
The longer leg = x
The shorter leg = x-7
Hypotenuse = x+7
Using Pythagoras theorem;

Either,
x= 0
Or,
x-28=0 =>x=28
As length cannot be zero, therefore,
Longer side = 28cm
Shorter side = x-7 = 28-7 = 21cm
Hypotenuse = x+7 = 28+7 = 35cm
The shorter leg is 21cm, longer leg is 28 cm and hypotenuse is 35cm.
Keywords: triangle, pythagoras theorem
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The first carpenter is 0.4464 of the way is ahead of the second carpenter
<u>Solution:</u>
Given, Two carpenters are building a fence
After 5 minutes, one carpenter is finished 4/7 of the way
Second carpenter finished 1/8 of the way
Now, let us find the work done by each carpenter

Then, extra work done by first carpenter over second carpenter = work done by first carpenter – work done by second carpenter
= 0.5714 – 0.125 = 0.4464
Hence, the 1st carpenter is 0.4464 of the way is ahead of the 2nd carpenter
y=cos(x)+2
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