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madam [21]
2 years ago
12

Are the triangles similar? If so, what postulate or theorem proves their similarity?

Mathematics
1 answer:
mafiozo [28]2 years ago
7 0

Answer:

SAS, two given sides are 40% longer, one angle is shared

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Show that the two triangles given beside are similar and calculate the lengths of sides PQ and PR.
Rina8888 [55]

9514 1404 393

Answer:

  • ΔABC ~ ΔPQR
  • PQ = 8
  • PR = 14

Step-by-step explanation:

Angles A and P are marked congruent; angles B and Q are marked congruent, so the triangles are similar by the AA similarity postulate. The similarity statement can be written ...

  ΔABC ~ ΔPQR by AA similarity

__

The ratio of sides of PQR to ABC is the ratio QR/BC = 12/6 = 2. That is, each side in the larger triangle is 2 times the length of the corresponding smaller side.

  PQ = 2·AB = 2·4 = 8

  PR = 2·AC = 2·7 = 14

The side lengths of interest are ...

  PQ = 8, PR = 14

5 0
2 years ago
What is always true about a like that slants downward from left to right
Norma-Jean [14]

Answer:

the slope of the line is negative

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
4/12 greater or less than 4/6
ICE Princess25 [194]
Less
4 out of 12 pieces
vs
4 out of 6 pieces
8 0
3 years ago
Read 2 more answers
Which of the following equations represents the perpendicular bisector of WX graphed below?
kotykmax [81]
The coordinates of the 2 given points are W(-5, 2), and X(5, -4).

First, we find the midpoint M using the midpoint formula:

\displaystyle{ M_{WX}= (\frac{x_1+x_2}{2},  \frac{y_1+y_2}{2} )=  (\frac{-5+5}{2},  \frac{2+(-4)}{2} )=(0, -1).

Nex, we find the slope of the line containing M, perpendicular to WX. We know that if m and n are the slopes of 2 parallel lines, then mn=-1.

The slope of WX is \displaystyle{ m= \frac{y_2-y_1}{x_2-x_1}= \frac{2-(-4)}{-5-5}= \frac{6}{-10}= -\frac{3}{5}.

Thus, the slope n of the perpendicular line is \displaystyle{  \frac{5}{3}.

The equation of the line with slope \displaystyle{ n= \frac{5}{3} containing the point M(0, -1) is given by:

\displaystyle{ y-(-1)=\frac{5}{3}(x-0)

\displaystyle{ y+1= \frac{5}{3}x

\displaystyle{ 3y+3=5x

\displaystyle{ 5x-3y-3=0

Answer: 5x-3y-3=0
8 0
3 years ago
PLEASE HELP!!! 14 POINTS!
Pepsi [2]
Area=1/2bh


add them
(1/2)ab+(1/2)c^2+(1/2)ab=
ab+(1/2)c^2
ab+(1/2)(a^2+b^2)
not sure which option to pick there are different preferences on what counts as 'simplified'




4. find area
area=LW
area=105*45=4725
depends on the area of the signs
answer is
4725/(areaof1sign)
anyway, round down your answer because you will have an incomplete sign if you don't




5. area=pir^2
1/2 of it is
area=1/2pir^2
area=(1/4)^2pir^2
area=pi((1/4)r)^2
the radius is now 1/4 of what it was originally, meaning that the diameter is also 1/4 of what it is now
we need to know diamater
answer is 1/4 of current diameter




3. unclear

4. area of 1 sign not given, answer is 4725/(areaof1sign), rounded DOWN to nearest integer

5. (404 error, diameter not found) answer is 1/4 of current diameter
8 0
3 years ago
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