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3 years ago

How to the medium in the dot line????!! I don't want my mom to be mad at my grade please!!!!!!

Mathematics

1 answer:

SVETLANKA909090 [29]3 years ago

7 0

Answer: To find the median, count the dots from left to right until you find the middle value.

Step-by-step explanation:

Ok so first it's not a dot line it's a dot plot. Second, let's define what a medium is. The medium is the "middle" of a sorted list of numbers. To find the Median, place the numbers in value order and find the middle number. Example: find the Median of {13, 23, 11, 16, 15, 10, 26}. The middle number is 15, so the median is 15. Tip to find the median from a list of value ordered numbers every time cross a number from each side. For example, if you cross 13 from above also cross 26 and if you cross 23 then also cross 10.

Back to your original question of how to find the medium on a dot plot you need to take all the numbers from your dotted line put them in order even if they are repeated and then cross each one on each side from right to left. Also remember if you cross out all the numbers right and left and end up with two numbers left then take them and add them and then divide by 2 and that will be the median.

An example is attached on here in order to help you understand what I am saying. Hope this helps. Your welcome and I hope you make your mama proud.

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After the outbreak of a mysterious disease the average wait time at a hospital increased by 70% before the outbreak the average

qaws [65]

Answer:

1.7m

Step-by-step explanation:

Given that 'm' was the waiting time before the outbreak

After the outbreak, waiting time increased by 70%.

This implies that :

70% of m increase

m + 70% of m

m + 70/100 of m

m + ( 70÷100 ) × m

m + 0.7m

= 1.7m

4 0

3 years ago

AB has coordinates A(-5,9) and B(7,- 7). Points P, Q, and I are collinear

VMariaS [17]

Answer:

$\overline{QT}$

Step-by-step explanation:

We want to find the coordinates of a certain point C(x,y) such that C divides $A(x_1,y_1)$ and $B(x_2,y_2)$ in the ratio m:n=3:2

The x-coordinate is given by:

$x=\frac{mx_2+nx_1}{m+n}$

The y-coordinate is given by:

$y=\frac{my_2+ny_1}{m+n}$

AB has coordinates A(-5,9) and B(7,- 7)

We substitute the values to get:

$x=\frac{3*7+2*-5}{3+2}$

$x=\frac{21-10}{5}$

$x=\frac{11}{5}$

and

$y=\frac{3*-7+2*9}{3+2}$

$y=\frac{-21+18}{5}$

$y=-\frac{3}{5}$

Therefore C has coordinates $(\frac{11}{5},-\frac{3}{5})$

The line segment that contains C is $\overline{QT}$

See attachment.

6 0

2 years ago

0.572 repeating as a fraction

valentinak56 [21]

572/1000, or 143/250.

4 0

3 years ago

A small circle is 8 points, a larger circle is 4 points, and the largest circle is 2 points.

Luda [366]

Answer:

depends on how hard from where you throw it what type of dart is it is it a metal or plastic tipped dart is it a solid metal dart is the body of the dart and the tip and the tail metal it depends so theres a ton of factors in the answer theres not just one answer

Step-by-step explanation:

7 0

2 years ago

In a certain region of space, the potential is given by v=2x−5x2y 3yz2. How much is the magnitude of the electric field at point

Masja [62]

The magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

<h3>How to calculate the electric field?</h3>

Since in a certain region of space, the potential is given by v = 2x − 5x²y 3yz²,

The electric field, E = -grad(V) where grad(V) = (dV/dx)i + (dV/dy)j + (dV/dz)k

Since V = 2x − 5x²y + 3yz²

dV/dx = d(2x − 5x²y + 3yz²)/dx

= d2x/dx - d5x²y/dx + d3yz²/dx

= 2 - 10xy + 0

= 2 - 10xy

dV/dy = d(2x − 5x²y + 3yz²)/dy

= d2x/dy - d5x²y/dy + d3yz²/dy

= 0 - 5x² + 3z²

= - 5x² + 3z²

dV/dz = d(2x − 5x²y + 3yz²)/dz

= d2x/dz - d5x²y/dz + d3yz²/dz

= 0 - 0 + 6z

= 6z

<h3>The electric field</h3>

So, E = -grad(V)

= -[(dV/dx)i + (dV/dy)j + (dV/dz)k]

= -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

So, the electric field at (-2, 2, 0) is

E = -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]

E = -[(2 - 10(-2)(2))i + (- 5(2)² + 3(0)²)j + (6(0))k]

E = -[(2 + 40)i + (- 5(4) + 0)j + (0)k]

E = -[42i + (-20 + 0)j + (0)k]

E = -[42i - 20j + 0k]

E = -42i + 20j - 0k

<h3>The magnitude of the electric field</h3>

So, the magnitude of E at (-2, 2, 0) is

|E| = √[(-42)² + 20² + 0²]

= √[1764 + 400 + 0]

= √2164

= 46.52 V/m

So, the magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m

Learn more about electric field here:

brainly.com/question/25751825

#SPJ12

3 0

2 years ago