How to the medium in the dot line????!! I don't want my mom to be mad at my grade please!!!!!!
1 answer:
Answer: To find the median, count the dots from left to right until you find the middle value.
Step-by-step explanation:
Ok so first it's not a dot line it's a dot plot. Second, let's define what a medium is. The medium is the "middle" of a sorted list of numbers. To find the Median, place the numbers in value order and find the middle number. Example: find the Median of {13, 23, 11, 16, 15, 10, 26}. The middle number is 15, so the median is 15. Tip to find the median from a list of value ordered numbers every time cross a number from each side. For example, if you cross 13 from above also cross 26 and if you cross 23 then also cross 10.
Back to your original question of how to find the medium on a dot plot you need to take all the numbers from your dotted line put them in order even if they are repeated and then cross each one on each side from right to left. Also remember if you cross out all the numbers right and left and end up with two numbers left then take them and add them and then divide by 2 and that will be the median.
An example is attached on here in order to help you understand what I am saying. Hope this helps. Your welcome and I hope you make your mama proud.
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Let's assume the frequency of sound be f and wave length is w.
Given that, the frequency of sound varies inversely as the wavelength.
So, we can set up an equation as following:
f*w = k Where k= constant of variation.
Other information is, the frequency of a musical note is 276 cycles per second when the wavelength is 1.2m.
So, next step is to plug in f = 276 and w = 1.2 in the above equation to get the value of k.
276 * 1.2 = k
So, k = 331.2
Next step is to plug in k = 331.2 in the above equation. So,
f * w = 331.2
Now we need to find the wave length : w when frequency : f = 600.
Therefore,
600 * w = 331.2
So, w = 0.552
Hence, the wave length is 0.552 m.
Hope this helps you!.
Hope this helped!
(Taken from a source but seemed right)
:)
(Taken from a source but seemed right)
:)