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2 years ago

How to the medium in the dot line????!! I don't want my mom to be mad at my grade please!!!!!!

Mathematics

1 answer:

SVETLANKA909090 [29]2 years ago

7 0

Answer: To find the median, count the dots from left to right until you find the middle value.

Step-by-step explanation:

Ok so first it's not a dot line it's a dot plot. Second, let's define what a medium is. The medium is the "middle" of a sorted list of numbers. To find the Median, place the numbers in value order and find the middle number. Example: find the Median of {13, 23, 11, 16, 15, 10, 26}. The middle number is 15, so the median is 15. Tip to find the median from a list of value ordered numbers every time cross a number from each side. For example, if you cross 13 from above also cross 26 and if you cross 23 then also cross 10.

Back to your original question of how to find the medium on a dot plot you need to take all the numbers from your dotted line put them in order even if they are repeated and then cross each one on each side from right to left. Also remember if you cross out all the numbers right and left and end up with two numbers left then take them and add them and then divide by 2 and that will be the median.

An example is attached on here in order to help you understand what I am saying. Hope this helps. Your welcome and I hope you make your mama proud.

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Compare the perimeters of the two regular figures. Which statement is true?

adell [148]

Answer:

(A). The perimeter of the octagon is greater than that of the hexagon.

Step-by-step explanation:

Since, hexagon consists of 6 sides and 6 angles, thus the measure of one angle of the hexagon will be= $\frac{(n-2){\timeS}180^{\circ}}{6}$

= $\frac{(6-2){\timeS}180^{\circ}}{6}$

= $\frac{(4){\timeS}180^{\circ}}{6}$

= $120^{\circ}$

Now, since MQ is the angle bisector of the one of the angle of the hexagon, therefore ∠QMP=60°.

Now, from ΔQMP. we have

$\frac{MP}{MQ}=cos60^{\circ}$

$MP=\frac{1}{2}$

Thus, the perimeter of the hexagon is:

$P=12{\times}MP$

$P=12{\times}\frac{1}{2}$

$P=6 units$

Thus, the perimeter of hexagon is 6 units.

Also, Since, octagon consists of 8 sides and 8 angles, thus the measure of one angle of the octagon will be= $\frac{(n-2){\timeS}180^{\circ}}{8}$

= $\frac{(8-2){\timeS}180^{\circ}}{8}$

= $\frac{(6){\timeS}180^{\circ}}{8}$

= $135^{\circ}$

Now, since AP is the angle bisector of the one of the angle of the octagon, therefore ${\angle}PAC=cos\frac{135}{2}$ .

From ΔAPC, we have

$AC=cos\frac{135}{2}$

Now, Perimeter of octagon is:

$P=16{\times}cos\frac{135}{2}$

$P=16{\times}0.382$

$P=6.122 units$

Thus, the perimeter of octagon is 6.122 units.

Now, the perimeter of octagon is greater than perimeter of the hexagon, thus option A is correct that is The perimeter of the octagon is greater than that of the hexagon.