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aksik [14]
3 years ago
13

Brainliest to correct help plz

Mathematics
1 answer:
Nastasia [14]3 years ago
7 0

Answer:

-68 1/5

Step-by-step explanation:

Brainliest?

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What is the tan invers of 3i/-1-i​
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<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)

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Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have

arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>

arg(<em>z</em>) = arctan(1) - <em>π</em>

arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>

arg(<em>z</em>) = -3<em>π</em>/4

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2 years ago
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3 years ago
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I need help with this problem please
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<em>n</em> must be 0, since <em>x </em>ⁿ = 1 for all positive, real <em>x</em> if <em>n</em> = 0. So the answer is A.

7 0
3 years ago
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