Answer: 7
Step-by-step explanation:
-if y is the width and the length of area k (see diagram), the difference between n and y is of 2 square sides, one at each side of y.
-therefore, assuming that n is a whole number and that there aren’t half squares, y must be a whole number too because, as previously said, n-y = 2 so y= n -2
-the only perfect square amongst the values for k you listed is 25, so taking n and y as whole numbers the only possible value for k is 25
-therefore y is 5 and n is 7 because n-y = 2 so y + 2 = n
Answer:
a) Find the common ratio of this sequence.
Answer: -0.82
b) Find the sum to infinity of this sequence.
Answer: 2.2
Step-by-step explanation:
nth term in geometric series is given by ![4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{0.549} \\r = 0.82](https://tex.z-dn.net/?f=4%5C%20th%20%5C%20term%20%3D%20ar%5En-1%5C%5C-2.196%20%3D%204r%5E%7B4-1%7D%20%5C%5C-2.196%2F4%20%3D%20r%5E%7B3%7D%20%5C%5Cr%20%3D%20%5Csqrt%5B3%5D%7B0.549%7D%20%5C%5Cr%20%3D%200.82)
where
a is the first term
r is the common ratio and
n is the nth term
_________________________________
given
a = 4
4th term = -2.196
let
common ratio of this sequence. be r
![4\ th \ term = ar^n-1\\-2.196 = 4r^{4-1} \\-2.196/4 = r^{3} \\r = \sqrt[3]{-0.549} \\r = -0.82](https://tex.z-dn.net/?f=4%5C%20th%20%5C%20term%20%3D%20ar%5En-1%5C%5C-2.196%20%3D%204r%5E%7B4-1%7D%20%5C%5C-2.196%2F4%20%3D%20r%5E%7B3%7D%20%5C%5Cr%20%3D%20%5Csqrt%5B3%5D%7B-0.549%7D%20%5C%5Cr%20%3D%20-0.82)
a) Find the common ratio of this sequence.
answer: -0.82
sum of infinity of geometric sequence is given by = a/(1-r)
thus,
sum to infinity of this sequence = 4/(1-(-0.82) = 4/1.82 = 2.2
Answer:
Length 34 cm
Width 8 cm
Step-by-step explanation:
Let
x-----> the length of the rectangle
y----> the width of the rectangle
we know that
The perimeter of rectangle is equal to
P=2(x+y)
P=84 cm
so
84=2(x+y)
42=x+y ----> equation A
x=4y+2 -----> equation B
substitute equation B in equation A and solve for y
42=(4y+2)+y
5y=42-2
y=40/5=8 cm
Find the value of x
x=4y+2 ----> x=4(8)+2=34 cm
The dimensions are
Length 34 cm
Width 8 cm
A/c = 8.....a = 8c
a * c = 2 ...a = 2/c
a/b = -16 ...a = -16b
a * b = -1....
b/c = -0.5
2/c = 8c
2 = 8c^2
1/4 = c^2
sqrt 1/4 = c
0.5 (or 1/2) = c <===
a * c = 2
0.5a = 2
a = 2/0.5
a = 4 <===
a = -16b
4 = -16b
4/-16 = b
-1/4 (or - 0.25) = b <===