Answer:
Let the 1st group be of students and 2nd group be of faculty.
n1 = 18
\bar{x}_{1} = 8.4
s1 = 7.3
n2 = 15
\bar{x}_{2} = 4.2
s2 = 3.8
1.
H0: =
HA: >
2.
Equality of variance test:
F = s12/s22
= 53.29/14.44
= 3.69
df-num = n1-1 = 17
df-den = n2-1 = 14
p-value = 0..008 < 0.05 i.e.H0 can be rejected and hence we can say that both populations do not have the same variances.
So, test-statistic will be calculated as follows:
[ Find the solution of this part in the attachment]
3.
df = 26
p-value = 0.0217
4.
E. It confirms the community college results because the p-value is much smaller.
Answer: He paid 13$ for the hat
Step-by-step explanation:
If you minus the ammount on the right then you will get 13
Answer: The radius will still be 4 units.
Step-by-step explanation:
Since it is a rigid transformation, nothing of the shape will change excepts it location meaning that the radius of the shape will still stay the same.
The radius is 4 and after a reflection , the radius will still be 4.
Answer:
i got 13.5 13.50 same thing.