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2 years ago

What is 3% of [(-0.5) * (- :)] ?

2 answers:

7 0

Solution for 0.5 is what percent of 3:

0.5:3*100 =

(0.5*100):3 =

50:3 = 16.666666666667

Now we have: 0.5 is what percent of 3 = 16.666666666667

Question: 0.5 is what percent of 3?

Percentage solution with steps:

Step 1: We make the assumption that 3 is 100% since it is our output value.

Step 2: We next represent the value we seek with $x$x.

Step 3: From step 1, it follows that $100\%=3$100%=3.

Step 4: In the same vein, $x\%=0.5$x%=0.5.

Step 5: This gives us a pair of simple equations:

$100\%=3(1)$100%=3(1).

$x\%=0.5(2)$x%=0.5(2).

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have

$\frac{100\%}{x\%}=\frac{3}{0.5}$
100%
x%=
3
0.5

Step 7: Taking the inverse (or reciprocal) of both sides yields

$\frac{x\%}{100\%}=\frac{0.5}{3}$
x%
100%=
0.5
3

$\Rightarrow x=16.666666666667\%$⇒x=16.666666666667%

Therefore, $0.5$0.5 is $16.666666666667\%$16.666666666667% of $3$3.

kap26 [50]2 years ago

5 0

Answer:

-0.015

I think so, but hope it helped!!

Step-by-step explanation:

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Can someone help me with this math homework please!

salantis [7]

Answer: h = 14

Step-by-step explanation:

7h-5(3h-8)-56 = -128

7h -15h+40-56 = -128

or, -8h-16= -128

or, -8h = -128 + 16

or, -8h = -112

or, 8h = 112

or, h = 112/8

so, h = 14

3 0

3 years ago

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which expression represents the distance between the two points x and y on the number line -4 and 3

Alika [10]

It would have to be 3 because distance can't be a negative number.

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3 years ago

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A shirt is on sale for 30% off. The original price is $26.98. What is the sale price?

Goshia [24]

100% - 30% = 70%

The shirt is selling for 70% of the original price.

Multiply the original price by 70%

26.98 x 0.70 = 18.89

The sale price is $18.89

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3 years ago

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Matthew invested $3,000 into two accounts. One account paid 3% interest and the other paid 8% interest. He earned 4% interest on

boyakko [2]

Answer:

Mathew invested $600 and $2400 in each account.

Solution:

From question, the total amount invested by Mathew is $3000. Let p = $3000.

Mathew has invested the total amount $3000 in two accounts. Let us consider the amount invested in first account as ‘P’

So, the amount invested in second account = 3000 – P

Step 1:

Given that Mathew has paid 3% interest in first account .Let us calculate the simple interest $(I_1)$ earned in first account for one year,

$\text {simple interest}=\frac{\text {pnr}}{100}$

Where

p = amount invested in first account

n = number of years

r = rate of interest

hence, by using above equation we get $(I_1)$ as,

$I_{1}=\frac{P \times 1 \times 3}{100}$ ----- eqn 1

Step 2:

Mathew has paid 8% interest in second account. Let us calculate the simple interest $(I_2)$ earned in second account,

$I_{2} = \frac{(3000-P) \times 1 \times 8}{100} \text { ------ eqn } 2$

Step 3:

Mathew has earned 4% interest on total investment of $3000. Let us calculate the total simple interest (I)

$I = \frac{3000 \times 1 \times 4}{100} ----- eqn 3$

Step 4:

Total simple interest = simple interest on first account + simple interest on second account.

Hence we get,

$I = I_1+ I_2 ---- eqn 4$

By substituting eqn 1 , 2, 3 in eqn 4

$\frac{3000 \times 1 \times 4}{100} = \frac{P \times 1 \times 3}{100} + \frac{(3000-P) \times 1 \times 8}{100}$

$\frac{12000}{100} = \frac{3 P}{100} + \frac{(24000-8 P)}{100}$

12000=3P + 24000 - 8P

5P = 12000

P = 2400

Thus, the value of the variable ‘P’ is 2400

Hence, the amount invested in first account = p = 2400

The amount invested in second account = 3000 – p = 3000 – 2400 = 600

Hence, Mathew invested $600 and $2400 in each account.

3 0

3 years ago

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Please help, I need input on if I did this correctly and you just substitute.

kow [346]

The value of h(t) when $t=\frac{15}{32}$ is 10.02.

Solution:

Given function $h(t)=-16t^2+15t+6.5$

To find the value of h(t) when $t=\frac{15}{32}$ :

$h(t)=-16t^2+15t+6.5$

Substitute $t=\frac{15}{32}$ in the given function.

$$h\left(\frac{15}{32} \right)=-16\left(\frac{15}{32} \right)^2+15\left(\frac{15}{32} \right)+6.5$

$$=-16\left(\frac{225}{1024} \right)+15\left(\frac{15}{32} \right)+6.5$

Now multiply the common terms into inside the bracket.

$$=-\left(\frac{3600}{1024} \right)+\left(\frac{225}{32} \right)+6.5$

Now, in the first term, the numerator and denominator both have common factor 16. So reduce the first term into the lowest term.

$$=-\left(\frac{225}{64} \right)+\left(\frac{225}{32} \right)+6.5$

To make the denominator same, take LCM of the denominators.

LCM of 64 and 32 = 64

$$=-\left(\frac{225}{64} \right)+\left(\frac{225\times2}{32\times2} \right)+6.5\times\frac{64}{64}$

$$=-\frac{225}{64} +\frac{450}{64}+\frac{416}{64}$

$$=\frac{-225+450+416}{64}$

$$=\frac{641}{64}$

= 10.02

$$h\left(\frac{15}{32} \right)=10.02$

Hence the value of h(t) when $t=\frac{15}{32}$ is 10.02.

8 0

3 years ago