Recall that an equation in slope-intercept form is as follows:

where m is the slope of the line, and (0,b) is the y-intercept.
Substituting m=-6, and b=-1/2 we get:

Simplifying the above result we get:

Answer:
Answer: 5 minutes
Step-by-step explanation:
Class of students - number of students that are boys = numbers of students that are girls
30 - 13 = 17
To change the number of students that are girls into percentage...
17/1 * 1/100 = 17/100
17/100 in a % form = 17%
The percentage of girls in the class is 17%
5 divided by 630 is about 0.007936
Answer:
The function for the outside temperature is represented by
, where t is measured in hours.
Step-by-step explanation:
Since outside temperature can be modelled as a sinusoidal function, the period is of 24 hours and amplitude of temperature and average temperature are, respectively:
Amplitude


Mean temperature


Given that average temperature occurs six hours after the lowest temperature is registered. The temperature function is expressed as:
![T(t) = \bar T + A \cdot \sin \left[2\pi\cdot\frac{t-6\,h}{\tau} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%20%5Cbar%20T%20%2B%20A%20%5Ccdot%20%5Csin%20%5Cleft%5B2%5Cpi%5Ccdot%5Cfrac%7Bt-6%5C%2Ch%7D%7B%5Ctau%7D%20%5Cright%5D)
Where:
- Mean temperature, measured in degrees.
- Amplitude, measured in degrees.
- Daily period, measured in hours.
- Time, measured in hours. (where t = 0 corresponds with 5 AM).
If
,
and
, the resulting function for the outside temperature is:
![T(t) = 85\º + 15\º \cdot \sin \left[\frac{t-6\,h}{24\,h} \right]](https://tex.z-dn.net/?f=T%28t%29%20%3D%2085%5C%C2%BA%20%2B%2015%5C%C2%BA%20%5Ccdot%20%5Csin%20%5Cleft%5B%5Cfrac%7Bt-6%5C%2Ch%7D%7B24%5C%2Ch%7D%20%5Cright%5D)