All categories

2 years ago

Richard had his car repaired at a body shop.

Mathematics

1 answer:

artcher [175]2 years ago

8 0

I think the answer is $460

You might be interested in

The sum of two numbers is -7. Five times the first number plus the second number is 1. What are the numbers?

arlik [135]

Answer:

Step-by-step explanation:

Well you only want the two equations so here they are.

x + y = -7

5*x + y = 1

I should give you the answer.

x = 2

y = -9 I think. These answers were done in my head.

4 0

3 years ago

Plz help I need it!!!!!!!!!!!!

AlekseyPX

Answer:

114°

Step-by-step explanation:

$? = \frac{1}{2} (53 \degree + 175 \degree) \\ \\ ? = \frac{1}{2} \times 228 \degree\\ \\ ? = 114 \degree$

8 0

3 years ago

Use induction to prove: For every integer n > 1, the number n5 - n is a multiple of 5.

nignag [31]

Answer:

we need to prove : for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

1) check divisibility for n=1, $f(1)=(1)^{5}-1=0$ (divisible)

2) Assume that $f(k)$ is divisible by 5, $f(k)=(k)^{5}-k$

3) Induction,

$f(k+1)=(k+1)^{5}-(k+1)$

$=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1$

$=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k$

Now, $f(k+1)-f(k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k$

$f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k$

Take out the common factor,

$f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)$ (divisible by 5)

add both the sides by f(k)

$f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)$

We have proved that difference between $f(k+1)$ and $f(k)$ is divisible by 5.

so, our assumption in step 2 is correct.

Since $f(k)$ is divisible by 5, then $f(k+1)$ must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

3 0

3 years ago

Volume of a cone

Monica [59]

Answer:

Answer

Step-by-step explanation:

Answered below :

6 0

2 years ago

Read 2 more answers

Jason needs to explain to his class how to use mental math to find the product of 400,000×50,000 how would u explain that

elena55 [62]

You would do 5 times 4 which is 20. then count how many zero's there are and put them after the 20.

4 0

3 years ago