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just olya [345]
3 years ago
5

Pls help (pic above)

Mathematics
2 answers:
wel3 years ago
4 0

Answer:

(7 + 5) + 1 = 12 + 1 = 13 \\ 7 + (5 + 1) = 7 + 6 = 13 \\ here \: we \: use \: assosiative \: \: property \\  of \: addition\\ option (b) \\ \: thank \: you

makvit [3.9K]3 years ago
3 0

Answer:

(7+5)+1 equals 12+1 which equals 13 7+(5+1) equals7+6 which equals to 13

Step-by-step explanation:

b: associative property of addition

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List the next four multiples of fraction 7/12
Sidana [21]
<h2>Hello!</h2>

The answer is:

\frac{14}{12}=\frac{7}{12}*2\\\\\\\frac{21}{12}=\frac{7}{12}*3\\\\\\\\\frac{28}{12}=\frac{7}{12}*4\\\\\\\\\frac{35}{12}=\frac{7}{12}*5

<h2>Why?</h2>

A multiple of a number is the repeated sum of itself, for example:

Multiple of the number 1 are: 1, 2, 3, 4, 5 and so...

Multiple of the number 3 are: 3, 6, 9, 12, 15 and so...

From the example we have:

Multiple of the number 3 are: Itself, (3+3), (3+3+3), (3+3+3+3), (3+3+3+3+3) and so...

So,

Multiple of \frac{7}{12} are:

\frac{14}{12}=\frac{7}{12}*2=\frac{7}{12}+\frac{7}{12}\\\\\\\frac{21}{12}=\frac{7}{12}*3=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{28}{12}=\frac{7}{12}*4=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{35}{12}=\frac{7}{12}*5=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}

Have a nice day!

6 0
4 years ago
Given f(x) = 2(4 – x)2, what is the value of F(15)? Record your answer and fat in the bubbles on your anser document​
kari74 [83]

Answer:

f(15) = 242

Step-by-step explanation:

Step 1: Define

f(x) = 2(4 - x)²

f(15) = x = 15

Step 2: Substitute and Evaluate

f(15) = 2(4 - 15)²

f(15) = 2(-11)²

f(15) = 2(121)

f(15) = 242

6 0
3 years ago
A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{(n-r)!r!}

Given : Total multiple-choice questions  = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= ^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84

No. of ways to answer 4 open-ended problems

= ^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= 84\times15=1260

Hence, the correct answer is option A) 1260

5 0
3 years ago
Decide whether the statement is true or false. If it is​ false, explain why. The union of the solution sets of 4xplus5equals13​,
postnew [5]

The given statement is false because it isn't an empty set!

<u>Step-by-step explanation:</u>

We have following sets of inequalities:

4x+5=13\\4x+5>13\\4x+5

From 4x+5=13 we get ,

4x = 8 \\x=2

Therefore solution set is x=2.

Now, for 4x+5>13 we get ,  

4x+5>13 \\4x>8\\x>2

Therefore solution set is x>2.

For 4x+5 we get ,

4x+5

Therefore solution set is x<2.

Now, the union of x=2, x<2 & x>2 is  -∞<x<∞. i.e. all possible values of x. And so above statement is false because it isn't an empty set!

4 0
3 years ago
Help,please,thankyou ​
Pavel [41]

Answer:

C.

Step-by-step explanation:

6 0
4 years ago
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