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Sidana [21]
3 years ago
10

Use the formula v^2-v^1/2^x_1^x to calculate the slope of the line

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
6 0

Answer

Writing??

Step-by-step explanation:

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Please follow the directions. Don't round immediate calculations.<br>Please try to get it right
marin [14]

Answer:

well without rounding <em>anything</em><em>,</em><em> </em><em>I</em><em> </em><em>got</em><em> </em><em>511.9999999992</em><em> </em><em>people</em><em> </em>

Step-by-step explanation:

so the ratio I used was 36 people for every 225 people( 225 because in total he asked 225 people) then I divided 3,200 into 225 to see how many times It would fit, the answer was 14.2222222222 then I multiplied that by 36 and my answer was 511.9999999992 people. I hope this helps, I tried to be as accurate as possible.

4 0
3 years ago
Mrs.Kunkleman asks her students to write the Pythagorean theorem in their own words
masha68 [24]

Step-by-step explanation:

The Pythagorean theorem can be understood as a mathematical relationship between the sides of a right triangle that helps to understand geometric problems in real situations, such as finding measurements, calculating areas, etc.

The theorem says that the square of the hypotenuse is equal to the sum of the squares on the other sides.

In a right triangle the hypotenuse is the longest side of the triangle, on the side opposite to its longest angle, and the other two sides will be the sides. So the Pythagorean theorem formula is:

a² = b² + c²

where a represents the hypotenuse and b and c the other sides.

5 0
3 years ago
When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected
jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

N=\frac{12.36}{0.03+0.55^t}

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

N=\frac{12.36}{0.33+0.55^0}

N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12

A. Initially, there were 12 deer.

B. N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0
3 years ago
Which measurement is equivalent to 850 mg?
stepladder [879]

Answer:

0.00187393

Hope this helps! :)

Please mark me the Brainliest!

6 0
3 years ago
HELP ME PLEASE!! Word problem, what's wrong? explain.
dmitriy555 [2]

Answer:

She made a mistake in Step 7.

Step-by-step explanation:

Step 1 through 6 are correct. Only from Step 6 to Step 7 the problem comes in: both sides of the equation are multiplied by x, however the x on the left side, by error, becomes 1. The correct state in Step 7 should look like this:

x(\frac{1}{2}P-x)=256

8 0
3 years ago
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