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Jobisdone [24]
3 years ago
5

Perpendicular to the line 2x + 3y = 12, passing through the point (7,3)

Mathematics
1 answer:
Hunter-Best [27]3 years ago
8 0

Answer:

2y-3x+15 = 0

Step-by-step explanation:

let the equation of the perpendicular line: y=mx+c.

Given equation : 2x+3y=12

                         => y=-2/3 x+4

so the sope of the equation is m1= -2/3.

as the two lines are mutually perpendicular,

so, m1*m2=-1

     => (-2/3)*m2= -1

     => m2= 3/2

the paerpendicular line : y=(3/2) x+c.

this line pass through (7,3)

so, 3 = (3/2)*7+c

  => c = -15/2

so the perpendicular line y = (3/2)*x -15/2

                                       => 2y-3x+15 = 0

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Please give detailed answer of the question.
Montano1993 [528]

The resulting coordinates for each row are (-2, 2), (0, 4),()2, 6), (6, 10) and (8,12) respectively

<h3>Functions and values</h3>

Given the linear function expressed as;

y = x + 4

where

x are the input values and y are the output values

If x = -2

y = -2+4

y = 2

The coordinate (x, y) will be (-2, 2)

If x = 0

y = 0+4

y = 4

The coordinate (x, y) will be (0,4)

If x = 2

y = 2+4

y = 6

The coordinate (x, y) will be (2, 6)

If x = 6

y = 6+4

y = 10

The coordinate (x, y) will be (6,10)

If x = 8

y = 8+4

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The coordinate (x, y) will be (8, 12)

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4 years ago
Which exponential function goes through the points (1, 16) and (4, 128)?
Rudiy27

Answer:

Option B is correct.

The exponential function goes through the points( 1, 16) and (4 , 128) is; f(x) = 8(2)^x

Step-by-step explanation:

The general form of the exponential function is given by;

y=f(x) = ab^x where a is the initial value and b is any value greater than 0.

If the exponential function goes through the points (1, 16) and (4, 128) we have;

16 = ab^1  

16 = ab                               ......[1]

and      

128 = ab^4                    .....[2]

Divide [2] by [1] we have;

\frac{128}{16} =\frac{ab^4}{ab}

Simplify:

8 = b^3 or

b^3 = 8

Taking cube root both sides we get;

b = \sqrt[3]{8} =\sqrt[3]{2^3}

Simplify:

b = 2

Substitute the value of b = 2 in [1] we get;

16 = a \cdot 2

Divide both sides by 2 we get;

\frac{16}{2} =\frac{2a}{2}

Simplify:

a = 8

Substitute the value of a and b in f(x) = ab^x

then we have;

f(x) = 8(2)^x

Therefore, the exponential function goes through the points( 1, 16) and (4 , 128) is; f(x) = 8(2)^x

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3 years ago
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