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Ivan
2 years ago
15

Pedro mixes 3/4 teespoon of plant food into each gallong of water.How much teaspoons of plant food should Pedro mix into 5 gallo

ns of water
Mathematics
2 answers:
Alex17521 [72]2 years ago
7 0
We need to do 3/4x5. 3/4 is the same as 0.75. 0.75x5= 3.75. If you put that back into a fraction it is 3 and 3/4. This means pearl needs to mix 3 and 3/4 teaspoons of plant food into the water.
Firlakuza [10]2 years ago
4 0
<span>Work:
</span>
1 gallon of water requires 3/4 teaspoon of plant food, so multiply 3/4 by 5

3/4  ×  5

Make 5 into a fraction

3/4  ×  5/1

Multiply the denominator by the denominator and the numerator by the numerator

 3   ×   5            15
----     ----    =   ------
 4   ×   1<span>             4

15/4  is an improper fraction, so make it a mixed fraction

15/4  =  3 and 3/4

Answer:

Pedro should mix 15/4  teaspoons or 3 and 3/4  teaspoons  of plant food into 5 gallons of water.</span>
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2 years ago
(8.218+9.93)+(17.782+0.07)
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First, using the order of operations(PEMDAS), you would solve what is inside the parenthesis. 
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3 years ago
For positive acute angles A and B, it is known that cos A= 20/29 and tan B= 11/60. Find the value of cos(A + B) in simplest form
jek_recluse [69]

Answer:

\displaystyle \cos(A + B) =\frac{969}{1769}

Step-by-step explanation:

We are given that:

\displaystyle \cos A=\frac{20}{29}\text{ and } \tan B=\frac{11}{60}

Where A and B are positive acute angles.

And we want to find cos(A + B).

Recall that cosine is the ratio of the adjacent side to the hypotenuse. Using this information, find the opposite side with respect to Angle A:

o=\sqrt{29^2-20^2}=21

Tangent is the ratio of the opposite side to the adjacent side. Find the hypotenuse with respect to Angle B:

h=\sqrt{11^2+60^2}=61

In summary:

With respect to Angle A, the adjacent side is 20, opposite is 21, and the hypotenuse is 29.

With respect to Angle B, the adjacent side is 60, the opposite is 11, and the hypotenuse is 61.

We can rewrite our expression as:

\displaystyle \cos(A+B)=\cos A\cos B-\sin A\sin B

Using the above information, substitute in the appropriate values. Note that since A and B are positive acute angles, all trigonometric values will be positive. Hence:

\displaystyle \cos(A + B)=\left(\frac{20}{29}\right)\left(\frac{60}{61}\right)-\left(\frac{21}{29}\right)\left(\frac{11}{61}\right)

Simplify:

\displaystyle \cos(A + B) =\frac{1200-231}{1769}=\frac{969}{1769}

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