What value of x solves the following equation?

If a train travels at the speed of 100 km how far will it travel in half an hour

choli [55]

Answer:

50 kilometers

Step-by-step explanation:

If it travels 100 in an hour, it would travel 50 in half

4 0

3 years ago

Read 2 more answers

Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

Comparing equations (A) and (B), we have

$5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.$

Thus,

$AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.$

8 0

3 years ago

I need help with these 2 questions!! please 20 points!!!

bezimeni [28]

9514 1404 393

Answer:

45 cm²
38 cm²

Step-by-step explanation:

The conventional way to work these problems is to make use of the formulas for areas of a triangle, rectangle, and semicircle. If you've used these formulas for a while, you recognize that they give you certain relationships that may make these problems easy to do mentally.

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1. The area of a triangle is half the product of height and width, so is equivalent to the area of a rectangle either half as high, or half as wide. We note that the width of the sail is 5 cm, so half that is 2.5 cm--exactly the same as the height of the boat's hull. That means we can add the height of the sail to the length of the boat, and the total area can be considered to be the same as that of a rectangle that is

2.5 cm high × (12 cm + 6 cm) long = (2.5)(18) cm² = 45 cm²

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2. The usual formula for the area of a circle is ...

A = πr²

When expressed in terms of diameter, this becomes ...

A = π(d/2)² = (π/4)d²

Then the area of a semicircle is half that, or (π/8)d². This is equivalent to the area of a rectangle that is "d" wide and "π/8·d" high. That is, the approximate area of the semicircle is that of a rectangle 4 cm high by (π/8·4 cm) = π/2 cm wide. In other words, the semicircle effectively adds π/2 cm to the left end of the 6 cm central rectangle of the figure.

As discussed above, the area of a triangle is equivalent to the area of a rectangle half as high. In this figure, the triangle is 10-6 = 4 cm wide, so can be considered to contribute 4/2 = 2 cm to the right end of the 6 cm central rectangle.

If we consider π ≈ 3, then the approximate area of the figure is ...

(4 cm)(3/2 cm + 6 cm + 2 cm) = (4)(9.5) cm² = 38 cm²

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The exact value is 4(8+π/2) = 32+2π ≈ 38.283 cm².

7 0

2 years ago

In the figure, m<2 = 44. What is the measure of <1?

fredd [130]

Answer:

m∠1 = 112°

Step-by-step explanation:

To solve for m∠1, we need to find the supplementary angle and subtract from 180°. We also know that m∠2 = 44° and the remaining two angles inside the triangle are the same because of the congruent sides, let's call each angle x.

Therefore m∠2 + x + x = 180; combine x's

m∠2 + 2x = 180; substitute m∠2 = 44°

44 + 2x = 180; subtract 44 from both sides

2x = 136; divide by 2

x = 68°

Therefore using the supplementary angle

x + m∠1 = 180 (because it is supplementary)

68 + m∠1 = 180; subtract 68 from both sides

m∠1 = 112°

7 0

2 years ago

A true-false quiz with 10 questions was given to a statistics class. Following is the probability distribution for the score of

mart [117]

Solution

Question 1:

- The formula for finding the mean score is that of the expected value formula. That is,

$\begin{gathered} E(x)=\sum_{i=1}p_i\times x_i \\ where, \\ p=\text{ The probability of getting a score of }x\text{ } \\ x=\text{ The actual score} \end{gathered}$

- Thus, the mean can be gotten as follows:

$\begin{gathered} \sum px=5\left(0.06\right)+6\left(0.16\right)+7\left(0.34\right)+8\left(0.23\right)+9\left(0.15\right)+10(0.06) \\ =7.43 \end{gathered}$

The mean score is 7.43

Question 2:

- The more students write the exam, the more the mean score will approach the theoretical mean score.

- The theoretical mean score is calculated above to be 7.43

- Thus, as more students write the quiz, their scores approach 7.43

7 0

1 year ago