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2 years ago

9

PLSS HELP IF YOU TURLY KNOW THISS

2 answers:

soldier1979 [14.2K]2 years ago

8 0

Answer:

$4x - 8 = 16 \\ 4x = 16 + 8 \\ 4x = 24 \\ x = \frac{24}{4} \\ x = 6 \\ thank \: you$

Gnom [1K]2 years ago

5 0

Answer:

x=6

Step-by-step explanation:

4x - 8 = 16

4x = 16 + 8

4x = 24 (divide both sides by 4 to get x)

4x/4 = 24/4

x = 6

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Pick two that are NOT equivalent to 6(5x + 4) - 10

bonufazy [111]

Answer:

a and c

Step-by-step explanation:

it would be a and c because the first expreesion in the sentace equals 54

<u><em>A and C are the only options that do not equal ( They both equal 24 not 54!) </em></u>

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3 years ago

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2 years ago

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Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

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5. $(\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}$

6.

$(-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}$

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3 years ago

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grin007 [14]

Answer:

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Step-by-step explanation:

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boyakko [2]

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