8. 70.5* 10. 30* 12. 5.1*
Answer:
the slope of the line that passes throught (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
given
(-4,3) and (-8,6)
slop=(6-3)/(-8-(-4))=(3)/(-8+4)=3/-4=-3/4
slope is -3/4
Step-by-step explanation:
Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
Answer:
d
Step-by-step explanation:
Answer:

Step-by-step explanation:
