Answer: Choice C.
Explanation: ASA stands for "angle side angle". To use ASA, we must have two pairs of congruent angles, as well as a pair of congruent sides. The sides must be between the angles in question
 
        
             
        
        
        
The lenght of each diagonals is 1.
        
                    
             
        
        
        
Answer:
The most correct option for the recursive expression of the geometric sequence is;
4. t₁ = 7 and tₙ = 2·tₙ₋₁, for n > 2
Step-by-step explanation:
The general form for the nth term of a geometric sequence, aₙ is given as follows;
aₙ = a₁·r⁽ⁿ⁻¹⁾
Where;
a₁ = The first term
r = The common ratio
n = The number of terms
The given geometric sequence is 7, 14, 28, 56, 112
The common ratio, r = 14/7 = 25/14 = 56/58 = 112/56 = 2
r = 2
Let, 't₁', represent the first term of the geometric sequence
Therefore, the nth term of the geometric sequence is presented as follows;
tₙ = t₁·r⁽ⁿ⁻¹⁾ = t₁·2⁽ⁿ⁻¹⁾ 
tₙ =  t₁·2⁽ⁿ⁻¹⁾ = 2·t₁2⁽ⁿ⁻²⁾ = 2·tₙ₋₁
∴ tₙ = 2·tₙ₋₁, for n ≥ 2
Therefore, we have;
t₁ = 7 and tₙ = 2·tₙ₋₁, for n ≥ 2.
 
        
             
        
        
        
Answer:
I believe that this is the best answer mark brainliest if it is
Step-by-step explanation:
The square root property should have been applied to both complete sides of the equation instead of to select
variables.
 
        
             
        
        
        
.45*10^4=4500
^ is the usual symbol for powers