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Arlecino [84]
3 years ago
5

Solve the equation using the Properties of Equality. 12 − c = −10 c =

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer:

  1. Subtraction Property of Equality
  2. Division Property of Equality
  3. c = 22

Step-by-step explanation:

12 - c = -10

~Subtract 12 to both sides

-c = -22

~Divide -1 to both sides

c = 22

Best of Luck!

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Need help with a math question
ale4655 [162]

Answer:

the coordinates of C' = (2,1)

Step-by-step explanation:

The coordinates of point C can be found by looking at the graph.

Coordinates of C are C= (6,3)

If ABCD is dilated by a factor of 1/3 then the coordinates of C' can be found by multiplying the coordinates of C by 1/3

C = (6,3)

C' =(1/3*6,1/3*3)

C' = (2,1)

So, the coordinates of C' = (2,1)

5 0
3 years ago
a culture started with 6,000 bateria after 6 hours,it grew to 7,200 .predict how many bacteria will be present after 17 hours ro
Genrish500 [490]

Answer:

10058

Step-by-step explanation:

The equation is of the form

y = ab^x

Where a is the initial value, y is the final  amount and x is the time

y = 6000 b^x

7200 = 6000 b^6

Divide each side by 6000

7200/6000 =  b^6

1.2 = b^6

Take the 6th root on each side

1.2 ^ 1/6 = b^6 ^ 1/6

1.030853321 = b

y = 6000 (1.030853321) ^ x

Let x = 17

y = 6000 (1.030853321) ^ 17

y=10057.68696

Rounding to the nearest whole number

y = 10058

7 0
3 years ago
Read 2 more answers
Given g(x)= -x-4, solve for x when g(x) =10
dalvyx [7]

Answer:

10 =  - x - 4 \\ 10 + 4 =  -  \times  \\ 14 =  - x \\ x =  - 14

5 0
2 years ago
Solve for the value of v
alisha [4.7K]

Answer:

4v+3+5v+6=180(being linear pair)

9v+9=180

9v=180-9

v=171/9

v=19

Step-by-step explanation:

7 0
3 years ago
9/20
NISA [10]

For this case we must find the solution of the following quadratic equation:

x ^ 2 + 5x + 7 = 0

Where:

a = 1\\b = 5\\c = 7

Then, the solution is given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting the values:

x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}

By definition we have:i ^ 2 = -1

x = \frac {-5 \pm \sqrt {3i ^ 2}} {2}\\x = \frac {-5 \pm i \sqrt {3}} {2}

Thus, we have two complex roots.

Answer:

The equation has no real roots.

4 0
3 years ago
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