Product = multiply
(6x-y)*(2x-y+2) =
12x^2 -8xy + 12x + y^2 - 2y
Answer:
The factors of given polynomial x =-1 , -2 and x =3
Step-by-step explanation:
<u><em>Step(i):</em></u>-
Given the polynomial
f(x) = x³ - 7x -6
put x =-1
f(-1) = (-1 )³- 7(-1) - 6 = -1+7-6=0
(x+1) is a one factor
By using synthetic division
x³ x² x constant
x=-1 ↓ 1 0 -7 -6
<u>↓ 0 -1 1 6</u>
<u> 1 -1 -6 0 </u>
<u />
<em>The polynomial x² - x - 6 </em>
<u><em>Step(ii):-</em></u>
The factors ( x+1)(x² - x - 6 ) = 0
x = -1 and x² - x - 6 =0
x =-1 and x² - 3x + 2 x - 6 =0
x =-1 and x (x -3) + 2( x-3) =0
x =-1 and (x+2)(x-3) =0
<u><em>Final answer:-</em></u>
The factors of given polynomial x =-1 , -2 and x =3
Craming last minute can lead to unecessary confusion however most examinars dont allow asking questions during exam
So if asking questions for clarification is allowed. A) is the odd one out
And these options are rather for test taking than learning
Answer:
Step-by-step explanation:
The average value theorem sets:
if f (x) is continuous in [a, b] and derivable in (a, b) there is a c Є (a, b) such that
, where
f(a)=f(π/2)=-4*sin(π/2) = -4*1= -4
f(b)=(3π/2)=-4*sin(3π/2) = -4*-1 = 4
⇒
c≅130
Answer:
Correct, it is 15
Step-by-step explanation:
Because 3 turns into 9, you also want to multiply the other by 3, so you’d do 5x3 to get 15
