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Liula [17]
3 years ago
5

The ratio of dogs to cats at the pet store is 4 to 5. If there are 18 dogs and cats in the store, how many of each are there?

Mathematics
1 answer:
Karolina [17]3 years ago
4 0

Answer:

23 cats

Step-by-step explanation:

So the ratio is basically saying that for every 4 dogs at the store there is one more cat, or 5 cats. 16 dogs there would be 20 cats. 18 dogs there would be approximately 23 cats if you would round up.

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I believe the answer is C
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3 years ago
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3(6d-24)=6(12+3d)<br> i need help
Alexxandr [17]

Answer:

No solutions

Step-by-step explanation:

Let's solve your equation step-by-step.

3(6d−24)=6(12+3d)

Step 1: Simplify both sides of the equation.

3(6d−24)=6(12+3d)

(3)(6d)+(3)(−24)=(6)(12)+(6)(3d)(Distribute)

18d+−72=72+18d

18d−72=18d+72

Step 2: Subtract 18d from both sides.

18d−72−18d=18d+72−18d

−72=72

Step 3: Add 72 to both sides.

−72+72=72+72

0=144

Answer:

There are no solutions.

5 0
3 years ago
An office manager estimates that she spends 40% of her 30-minute lunch
Elina [12.6K]

Answer:

answer = 12 min

Step-by-step explanation:

40% of 30 min = ?

10% of 30 min = 3

3*4 = 12

Thus, she spends 12 min of her 30 min lunch driving

P.S.

If the answer is wrong, then multiply it by two and retry

4 0
3 years ago
On one day a pet store sells 2 birds 6 gerbils 3 fish and 3 hamsters whats the data and relative frequency as a percent?
bonufazy [111]

Answer:

Birds F_b=14.3\%

Gerbils F_g=42.9\%

Fish F_f=21.4\%

Hamsters F_h=21.4\%

Step-by-step explanation:

From the question we are told that:

Sales

Number of birds  n_b=2

Number of gerbils  n_g=6

Number of fish  n_f=3

Number of hamsters  n_h=3  

Generally the frequency for birds F_b is mathematically given b

F_b=\frac{n_b}{n}*100

F_b=\frac{2}{14}*100

F_b=14.3\%

Generally the frequency for Gerbils F_g is mathematically given b

F_g=\frac{n_g}{n}*100

F_g=\frac{6}{14}*100

F_g=42.9\%

Generally the frequency for fish F_f is mathematically given b

F_f=\frac{n_f}{n}*100

F_f=\frac{3}{14}*100

F_f=21.4\%

Generally the frequency for fish F_h is mathematically given b

F_h=\frac{n_h}{n}*100

F_h=\frac{3}{14}*100

F_h=21.4\%

5 0
3 years ago
Please go to my profile and answer my last question
Alex Ar [27]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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