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vekshin1
3 years ago
14

I am lazy answer these 3 questios for meh

Mathematics
1 answer:
eimsori [14]3 years ago
3 0

Answer:

#

Tiffany ate ¼ of a pizza. If there were 16 slices of pizza to begin with, how many slices did Tiffany eat?

Solution given;

Since total=16 slices

Tiffany ate =¼ part of pizza

now

Tiffany ate=¼ part of 16 slices=¼*16=4slices

Tiffany ate 4 slices.

#

Katelyn ate ⅓ of an apple pie, and Chad ate 3/8 of the same pie. What fraction of the pie was eaten?

Solution given:

Katelyn ate ⅓ of an apple pie

Chad ate ⅜ of the same pie

now

eaten fraction of the pie =⅓+⅜=\frac{1*8+3*3}{3*8}

<h3>=\frac{17}{24} fraction of the pie was eaten.</h3>

#

Vince has ½ ton of gravel to spread equally in 8 square yards for his driveway. How many tons of gravel will be spread in each square yard?

Solution given:

8square yards=½ ton of gravel

each square yards=½*⅛=\frac{1}{16}ton of gravel

Candice spent 345 hours, and Shane spend 2 10 hours at track practice over the weekend. How many more hours did Candice spend than Shane at track practice?

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Use scientific notation to find the product of 7.13 × 10 -3 and 40.
OleMash [197]

Answer:

(7.13 × 10^-3) x 40 = 285.2 x 10^-3 = 2.9 x 10^-1

Step-by-step explanation:

I  think this is the answer i hope if it right or not but aleast I try on it .

4 0
3 years ago
The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out t
yulyashka [42]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   C

b

    C

c

    C

d  

     A

Step-by-step explanation:

From the question we are told that

    The population mean is  \mu  =  0.5 \  in

     

Generally the Null hypothesis is  H_o  :  \mu = 0. 5 \ in

                The Alternative hypothesis is  H_a  :  \mu  \ne  0.5 \ in

Considering the parameter given for part a  

       The sample size is  n =  15  

        The  test statistics is  t =  1.66

        The level of significance \alpha  =  0.05

The degree of freedom is evaluated as

            df =  n-  1

           df =  15-  1

           df =  14

Using the critical value calculator at (social science statistics web site )  

           t_{\frac{\alpha}{2} ,df } =  t_{\frac{0.05 }{2} ,14} =  2.145

We are making use of this  t_{\frac{\alpha }{2} } because it is a one-tail test

Looking at the value of  t and t_{\frac{\alpha }{2} } the we see that  t < t_{\frac{\alpha }{2}  } so the null hypothesis would not be rejected

Considering the parameter given for part b  

       The sample size is  n =  15  

        The  test statistics is  t =  -1.66

        The level of significance \alpha  =  0.05

The degree of freedom is evaluated as

            df =  n-  1

           df =  15-  1

           df =  14

Using the critical value calculator at (social science statistics web site )  

           t_{\frac{\alpha}{2} ,df } =  t_{\frac{0.05 }{2} ,14} =  -2.145

Looking at the value of  t and t_{\frac{\alpha}{2} ,df } the we see that t does not lie in the area covered by  t_{\frac{\alpha}{2}  , df } (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

 

Considering the parameter given for part  c

       The sample size is  n =  26  

        The  test statistics is  t =  -2.55

        The level of significance \alpha  =  0.01

The degree of freedom is evaluated as

            df =  n-  1

           df =  26-  1

           df =  25

Using the critical value calculator at (social science statistics web site )  

           t_{\frac{\alpha}{2} ,df } =  t_{\frac{0.01 }{2} ,25} =  2.787

Looking at the value of  t and t_{\frac{\alpha }{2} } the we see that t does not lie in the area covered by  t_{\alpha , df } (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  d

       The sample size is  n =  26  

        The  test statistics is  t =  -3.95

        The level of significance \alpha  =  0.01

The degree of freedom is evaluated as

            df =  n-  1

           df =  26-  1

           df =  25

Using the critical value calculator at (social science statistics web site )  

           t_{\frac{\alpha}{2} ,df } =  t_{\frac{0.01 }{2} ,25} =  -2.787

Looking at the value of  t and t_{\frac{\alpha}{2}  } the we see that  t  lies in the area covered by  t_{\alpha , df } (i.e the area from -2.787 downwards on the normal distribution curve ) hence we  reject the null hypothesis

6 0
3 years ago
The length of a rectangle is 6 meters more than three times the width. The perimeter of the rectangle is 44 meters. What are the
Oksana_A [137]

Answer:

width=4

length=18

Step-by-step explanation:

length-6=3width

length=3width+6

also:

perimeter of the rectangle=2(length+width)

44/2=width+length

22=width+length

now put the length we found in the 1st equation, in 22=width+length

=>22=width+3width+6

22-6=4width

width=4

now do the exact same thing with one of these equations:

22=width+length

length=3width+6

I'd do it with the 1st one:

22=4+length

22-4= length

length=18

6 0
4 years ago
What s 80% of 60 questions.
Maslowich

Answer:

48 questions

Step-by-step explanation:

.8 * 60 = 48

3 0
3 years ago
Read 2 more answers
Find the balance of the account using the simple interest formula of I=Prt
Sever21 [200]

Answer:

$8.75

Step-by-step explanation:

Simple interest can be determined using this formula :

principal x time x interest rate

principal = $1400  

time = 6 months = 6/12 = 0.5

interest rate = 1.25%

$1400 x 0.5 x 0.0125 = $8.75

5 0
3 years ago
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