We can find a formula for nth term of the given sequence as follows:
1, 5, 12, 22, 35
The 1st differences between terms:
4, 7, 10, 13
The 2nd differences :
3, 3, 3
Since it takes two rounds of differences to arrive at a constant difference between terms, the nth term will be a 2nd degree polynomial of the form:
, where c is a constant. The coefficients a, b, and the constant c can be found.
We can form the following 3 equations with 3 unknowns a, b, c:

Solving for a, b, c, we get:
a = 3/2, b = -1/2, c = 0
Therefore, the nth term of the given sequence is:

N; n + 2 - the two consecutive even integers
n + 3(n + 2) = 46
n + 3n + 6 = 46 <em> |subtract 6 from both sides</em>
4n = 40 <em> |divide both sides by 4</em>
n = 10
n + 2 = 10 + 2 = 12
<u>Answer: 10 and 12.</u>
I honestly don't know but I think it would come out to be 4/5