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Yanka [14]
3 years ago
8

I WILL GIVE BRAINLIEST

Mathematics
1 answer:
Novay_Z [31]3 years ago
5 0

Answer: A

Step-by-step explanation:

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At a carnival, the probability that a person will win a prize at the ring-toss
dimaraw [331]

Answer:

a) 0.20363

b) 0.00113

c) 0.77378

d) 0.18868

Step-by-step explanation:

Complete Question

At a carnival, the probability that a person will win a prize at the ring-toss game has been found to be (1/20). What is the probability that a prize will be won by exactly

a. 1 of the next 5 players?

b. 3 of the next 5 players?

c. 0 of the next 5 players?

d. 2 of the next 20 players?​

Solution

This is a binomial distribution problem

A binomial experiment is one in which the probability of success doesn't change with every run or number of trials.

It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure.

The outcome of each trial/run of a binomial experiment is independent of one another.

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 5, 20

x = Number of successes required = 1, 3, 0, 2

p = probability of success = probability of winning a prize in the ring-toss = (1/20) = 0.05

q = probability of failure = probability of NOT winning a prize in the ring-toss = 1 - (1/20) = (19/20) = 0.95

a. 1 of the next 5 players?

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 5

x = Number of successes required = 1

p = probability of success = 0.05

q = probability of failure = 0.95

P(X = 1) = ⁵C₁ (0.05)¹ (0.95)⁵⁻¹ = 0.2036265625 = 0.20363

b) 3 of the next 5 players?

n = total number of sample spaces = 5

x = Number of successes required = 3

p = probability of success = 0.05

q = probability of failure = 0.95

P(X = 3) = ⁵C₃ (0.05)³ (0.95)⁵⁻³ = 0.001128125 = 0.00113

c. 0 of the next 5 players?

n = total number of sample spaces = 5

x = Number of successes required = 0

p = probability of success = 0.05

q = probability of failure = 0.95

P(X = 0) = ⁵C₀ (0.05)⁰ (0.95)⁵⁻⁰ = 0.7737809375 = 0.77378

d. 2 of the next 20 players?​

n = total number of sample spaces = 20

x = Number of successes required = 2

p = probability of success = 0.05

q = probability of failure = 0.95

P(X = 2) = ²⁰C₂ (0.05)² (0.95)²⁰⁻² = 0.18867680127 = 0.18868

Hope this Helps!!!

4 0
3 years ago
Determine the area, in square feet, of the smallest square that can contain a circle with a radius of 8 feet.
bixtya [17]

Answer: 256ft Squared

Explanation:

Length= 8 x 2=16ft

Area: 16^2 (16 x 16)= 256ft^2

3 0
3 years ago
Pls answer this question quickly.
natali 33 [55]

Below is the pseudocode of the "test" algorithm:

algorithm "test"

var

A: VECTOR [1..3,1..3] OF WHOLE

C, L, M: WHOLE

start

RANDOM 1,50

FOR L OF 1 ATE 3 KNIFE

FOR C OF 1 ATE 3 KNIFE

READ (A [L, C])

SE (L = 1) E (C = 1) ENTAO

M <-A [L, C]

END IF

IF A [L, C]> M ENTAO

M <-A [L, C]

END IF

FIMPARA

FIMPARA

WRITING ("**** MATRIX A ****")

FOR L OF 1 ATE 3 KNIFE

FOR C OF 1 ATE 3 KNIFE

WRITE (A [L, C]: 4)

FIMPARA

WRITING

FIMPARA

WRITING (M)

final algorithm

On this algorithm, analyze the following sentences:

I. A is a matrix whose elements are integers generated randomly.

II. A is an order 3 matrix.

III. At the end of its execution, the algorithm prints the smallest value of the matrix.

IV. At the end of its execution, the algorithm prints the largest value of the matrix.

Now, mark the alternative that presents the CORRECT answer.

Alternatives:

The)

Only affirmative III is correct.

B)

Affirmations I and II are correct.

w)

Affirmations I, II and III are correct.

(d)

Affirmations I, II and IV are correct.

and)

All statements are correct.

8 0
3 years ago
there were 432 animals at the zoo. the zookeeper made 9 different habitats for the animals. if the animals were spread evenly am
Irina-Kira [14]
48 animals would be in each habitat. how i got that answer is 432 divided by 9 = 48
6 0
3 years ago
Read 2 more answers
Monica has a $1000 bond with a 5.5% coupon. Monica purchased this bond for $1025. What is the yield of this new bond?
arsen [322]

Answer:

Annual return on the bond is 1000*0.055 = $55 per year  

Yield = return/price = 55/1025 ≈ 0.0537 ≈ 5.4%


6 0
3 years ago
Read 2 more answers
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