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EleoNora [17]
3 years ago
10

A construction company plans to invest in a building project. There is a 30% chance that the company will lose $30,000, a 40% ch

ance of a break even, and a 30% chance of a $60,000 profit. Based ONLY on this information, what should the company do?
The expected value is $9,000.00, so the company should proceed with the project.
B) The expected value is $18,000.00, so the company should proceed with the project.
C) The expected value is −$9,000.00, so the company should not proceed with the project.
D) The expected value is −$18,000.00, so the company should not proceed with the project.
Mathematics
1 answer:
Gnom [1K]3 years ago
4 0

Answer: Option 'A' is correct.

Step-by-step explanation:

Since we have given that

30% chance that the company will lose $30000.

40% chance of a break even that there is no loss and no profit.

30% chance that the company will profit $ 60000.

As we know the formula for "Expectation":

So, Expected value will be

\frac{30}{100}\times (-30000)+\frac{40}{100}\times 0+\frac{30}{100}\times 60000\\\\=03\times (-30000)+0.4\times 0+0.3\times 60000\\\\=-9000+18000\\\\=\$9000

Expected value is $9000. So, the company should proceed with the project.

Hence, Option 'A' is correct.

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During their last game, the Miami Dolphins scored ͸ times for a total score of ͵Ͳ points. They scored ͹ points for each touchdow
Karolina [17]

Answer:

The Miami Dolphins had 3 touchdowns and 3 field goals.

Step-by-step explanation:

It is given that During their last game, the Miami Dolphins scored 6 times, for a total score of 30 points. They scored 7 points for each touchdown and 3 points for each field goal.

We need to write and solve the system of equations to find the total touchdowns and field goals scored.

Let x represents the number of touchdowns.

Let y be the number of field goals.

It is given that the Miami Dolphins scored 6 times

x+y=6

x=6-y....(1)

They scored 7 points for each touchdown and 3 points for each field goal.

The total score is 30 points:

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Put the value of x from equation (1) into equation (2).

7( 6-y)+3y=30

42-7y+3y=30

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-4y=-12

y=3

Put y = 3 in equation 1.

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4 0
3 years ago
Weights of cars passing over a bridge part 2<br>​
DaniilM [7]

Step-by-step explanation:

The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.

Given:

mean,  mu = 3550 lbs (hope I read the first five correctly, and it's not a six)

standard deviation, sigma = 870 lbs

weights are normally distributed, and assume large samples.

Probability to be estimated between W1=2800 and W2=4500 lbs.

Solution:

We calculate Z-scores for each of the limits in order to estimate probabilities from tables.

For W1 (lower limit),

Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069

From tables, P(Z<Z1) = 0.194325

For W2 (upper limit):

Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954

From tables, P(Z<Z2) = 0.862573

Therefore probability that weight is between W1 and W2 is

P( W1 < W < W2 )

= P(Z1 < Z < Z2)

= P(Z<Z2) - P(Z<Z1)

= 0.862573 - 0.194325

= 0.668248

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6 0
4 years ago
For a Saturday matinee, adult tickets cost $8.50 and kids under 12 pay only $7.00. If 80 tickets are sold for a total
jolli1 [7]

Answer:

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Step-by-step explanation:

<u>Given</u>

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Let the adult ticket be a and kids be k

<u>We got equations</u>

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<u>From the first equation we get</u>

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<u>Substituting k in the second equation</u>

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<u>Then finding k</u>

  • k = 80 - 30 = 50

8 0
4 years ago
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