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denis23 [38]
4 years ago
15

If the slope of a line is 2and its y-intercept is 5 what is theequation of the line

Mathematics
2 answers:
Scorpion4ik [409]4 years ago
5 0
To make this easier the answer is, "y = 2x + 5"
stira [4]4 years ago
4 0
Have you tried working on it
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Find the value of the missing variables.
dsp73

Answer:

x^{\circ}=35^{\circ}\\ \\y^{\circ}=55^{\circ}

Step-by-step explanation:

The measure of arc which the right triange cuts from the circle is 70^{\circ}, this means the central angle has the same measure.

Angle with measure x^{\circ} is inscribed angle subtended on the given arc. Its measure is half the measure of the central angle, hence

x^{\circ}=\dfrac{1}{2}\cdot 70^{\circ}=35^{\circ}

Angles with measures x^{\circ} and y^{\circ} are complementary angles (add up to 90°), so

y^{\circ}=90^{\circ}-35^{\circ}=55^{\circ}

6 0
3 years ago
If an^2 =b then in terms of a and b , n=?
kompoz [17]

Answer:

√b/a

Step-by-step explanation:

  • an^2 =b
  • n^2=b/a
  • n=√b/a
4 0
3 years ago
Read 2 more answers
I need help with this question fast! i don't have a lot of time! can someone help me please???
jarptica [38.1K]
16x^4-81y^4  difference of perfect squares...

(4x^2-9y^2)(4x^2+9y^2)  that's one of the equivalents...

(2x+3y)(2x-3y)(4x^2+9y^2)  that's another one of them...
5 0
3 years ago
How to draw a graph your cost c to buy w pounds of walnuts at 6$\lb is represented by c =6w
Triss [41]
Y = 6x put it in a graphic calculator or go to desmos.com
7 0
3 years ago
Find the value of sin(a/2) if cosa= 12/13<br>​
daser333 [38]

Answer: sin\frac{a}{2} = ± \frac{1}{\sqrt{26} }

Step-by-step explanation:

We very well know that,

cos2A=1−2sin²A

⟹ sinA = ±\sqrt{(1-} \frac{cos2A}{2} )

As required,  set A = \frac{a}{2}   &   cos a=  \frac{12}{13}    ,thus we get

sin \frac{a}{2} =± \sqrt{\frac{1-cos a}{2} }  

∴ sin\frac{a}{2} =±\sqrt{\frac{1-\frac{12}{13} }{2} } = ± \frac{1}{\sqrt{26} }

   since ,360° < \frac{a}{2} <450°

             ,180° < \frac{a}{2} <225°

Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.

hope it helped!

   

5 0
3 years ago
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