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IRINA_888 [86]
3 years ago
14

Help meee please on this one

Mathematics
1 answer:
egoroff_w [7]3 years ago
3 0

Answer:

The area of the field is 10.24 times the area of the playground

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Molly had a $12 gift card to download music. She bought 8 songs that each cost the same amount. Write a variable equation, then
inn [45]

Answer:

1.Equation ----- 8x=12

2. x=1.5

3. cost of a single song is $1.5

4.$12 gift card will download 8 songs

Step-by-step explanation:

The amount of money the gift card holds is $12

Number of songs bought= 8 songs

Let the cost of a single song to be =$x

The cost of 8 songs will be =$x × 8=$ 8x

So the 8 songs will all cost $12

This means; $ 8x = $12

Equation------ 8x=12

Finding cost of a single song

8x=12------------------divide by 8 both sides

x=12/8------------------simplify

x=3/2 = $ 1.5

Checking for solution

if a single song costs $1.5 , who many songs can a gift card with $12 download?

Here we divide $12 by $1.5 = $12/$1.5= 8 songs------------correct number of songs as mentioned in the question.

7 0
3 years ago
Let g(x)= -3x and h(x) x^2+3 Find (g°h)(0)
raketka [301]
<h3>Answer is   -9</h3>

=================================

Work Shown:

(g°h)(x) is the same as g(h(x))

So, (g°h)(0) = g(h(0))

Effectively h(x) is the input to g(x). Let's first find h(0)

h(x) = x^2+3

h(0) = 0^2+3

h(0) = 3

So g(h(x)) becomes g(h(0)) after we replace x with 0, then it updates to g(3) when we replace h(0) with 3.

Now let's find g(3)

g(x) = -3x

g(3) = -3*3

g(3) = -9

-------

alternatively, you can plug h(x) algebraically into the g(x) function

g(x) = -3x

g( h(x) ) = -3*( h(x) ) ... replace all x terms with h(x)

g( h(x) ) = -3*(x^2 + 3) ... replace h(x) on right side with x^2+3

g( h(x) ) = -3x^2 - 9

Next we can plug in x = 0

g( h(0) )  = -3(0)^2 - 9

g( h(0) ) = -9

we get the same result.

7 0
3 years ago
10x-5 9x+2 is my equation and I don’t know how to solve it I really need help,someone please help me solve it.
Ostrovityanka [42]

9514 1404 393

Answer:

  x = 7

Step-by-step explanation:

You solve a linear equation by putting the variable on one side of the equal sign and a constant on the other side. Here, variables and constants are on both sides of the equal sign, so you need to separate them.

The basic idea is that you add the opposite of any term you don't want. Whenever you perform any operation (like "add"), <em>you must do it to both sides of the equation</em>.

We observe that x-terms have coefficients of 10 and 9. We choose to add the opposite of 9x to both sides:

  10 -9x -5 = 9x -9x +2

  x -5 = 2 . . . . simplify

Now, we still have -5 on the left, where we don't want it. So, we add its opposite (+5) to both sides:

  x -5 +5 = 2 +5

  x = 7 . . . . simplify

The solution is x = 7.

_____

<em>Additional comment</em>

If we were to end up with an x-coefficient other than 1, we would divide both sides of the equation by that coefficient. This will leave the x-term with a coefficient of 1.

8 0
2 years ago
Hailey received some cash for birthday. She spent $14.48 on a CD and donated $25.00 to charity. She put half of what was left in
DaniilM [7]
Work backwards.

After she put half of what she had left in, she had 17.76.

Multiply by 2:

17.76 * 2 = 35.52

Add 25:

35.52 + 25 = 60.52

Add 14.48:

75

So she received $75 on her birthday.
8 0
3 years ago
Read 2 more answers
Explain why their are no solutions to the system of inequalities <br> y ≤2x-5 <br> y ≥2x+1
rosijanka [135]

Answer:

Sorry this is late and I think this is right.

They are both parallel, they have the same slope, and do <em>not </em>intersect. If you were to draw a slope out for it, you would find this to be true.

For example: Say the question called for you to explain why there aren't any solutions to these system of inequalities:

<em>y < - 1/2x -3</em>

<em>y > 1/2x + 2</em>

<em>y= -x/2 -3</em> and <em>y= -x/2 + 2 </em>have the same exact slope, are parallel, and never intersect. The first line is 5 units below the second line when x = 0. Because the lines are parallel, it is always below the second line. The solutions of y < - x/2 -3 are the points in the plane below the first line. The solutions of y > 1/2 + 2 are points above the second line.

I hope this helps you. Good luck on whatever you're working on and stay safe! Please let me know if this helped you or didn't.

7 0
3 years ago
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