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3 years ago

Which ones are the distance formula and midpoint formula?

Mathematics

1 answer:

lutik1710 [3]3 years ago

7 0

Answer:

The distance formula is $d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)2}$

The midpoint formula is $\left(\frac{x_1\:+x_2}{2}\right),\left(\frac{y_1-y_2}{2}\right)$

Step-by-step explanation:

apply the pythagorean theorem on a coordinate grid

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The length of a rectangle is two less than four times the width. If the perimeter is 26 cm, find the dimensions of the rectangle

gulaghasi [49]

Answer:

w = 3

l = 10

Step-by-step explanation:

l = 4w-2

P = 26cm

P = (l + w) × 2

26 = (4w-2+w) ×2

26 = (4w + w - 2) × 2

26 = ( 5w - 2 ) × 2

26 ÷ 2 = 5w -2

13 = 5w - 2

13 + 2 = 5w

15 = 5w

w = 3

l = 4w - 2

l = (4 × 3) -2

l = 12 - 2

l = 10

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3 years ago

SURFACE AREA OF RECTANGULAR PRISMS

Sergeeva-Olga [200]

Answer:

Lateral is 196

Step-by-step explanation:

7 cm times 10 cm times 2.8 cm

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3 years ago

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Dmitry [639]

The value of $\log _{6}(36)$ is 2.

Solution:

Given expression is $\log _{6}(36)$ .

To evaluate the expression:

$\log _{6}(36)$

36 can be written as 6².

$=\log _{6}\left(6^{2}\right)$

Using log rule: $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$

$=2 \log _{6}(6)$

Using log rule: $\log _{a}(a)=1$ so that $\log _{6}(6)=1$

= 2(1)

= 2

$\log _{6}(36)=2$

Hence the value of $\log _{6}(36)$ is 2.

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Answer:

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Step-by-step explanation:

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