Answer:
1) 10.55%
2) 30.77%
Step-by-step explanation:
52/52•39/51•26/50•13/49 = 0.105498... ≈ 10.55%
100% chance you draw a unique card on the first draw
51 cards left of which 13(3) = 39 are unique suit for your second draw
50 cards left of which 13(2) = 26 are unique suit for your third draw
49 cards left of which 13(1) = 13 are unique suit for your forth draw.
Two balls are already green
Leaves 4 red balls in a field of 13 balls
4/13 = 0.307692... ≈ 30.77%
(Problems 1b and 2b are cut off in the photo)
1a Problem:
(-3,1)
(-3,5)
(-7,1)
2a Problem:
(6,2)
(3,5)
(10,7)
*Psst, I need one more brainliest answer to rank up, so if you gave that to me, it would be very appreciated, thanks :)*
Answer:
a
Step-by-step explanation:
correct on edge
<h3>Given</h3>
Two positive numbers x and y such that xy = 192
<h3>Find</h3>
The values that minimize x + 3y
<h3>Solution</h3>
y = 192/x . . . . . solve for y
f(x) = x + 3y
f(x) = x + 3(192/x) . . . . . the function we want to minimize
We can find the x that minimizes of f(x) by setting the derivative of f(x) to zero.
... f'(x) = 1 - 576/x² = 0
... 576 = x² . . . . . . . . . . . . multiply by x², add 576
... √576 = x = 24 . . . . . . . take the square root
... y = 192/24 = 8 . . . . . . . find the value of y using the above equation for y
The first number is 24.
The second number is 8.
