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frozen [14]
3 years ago
6

Let x=2. Evaluate the expression. x+4/3x enter your answer in the box

Mathematics
1 answer:
maria [59]3 years ago
8 0

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Solve x+4/3x , if x = 2.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

To solve this equation, at first, let's just substitute x with 2.

So, the equation becomes ⇨ 2+4/3×2

\tt \: \frac{x + 4}{3x}  \\  \\  \tt \:\dashrightarrow \frac{(2) + 4}{3(2)}  \\  \\ \tt \: Add \:  2  \: and  \: 4  \: to  \: get  \: 6. \\  \\ \tt \: = \frac{6}{3\times 2}  \\  \\ \tt \:Multiply  \: 3  \: and \:  2  \: to  \: get \:  6. \\  \\  \tt \:=  \frac{6}{6}  \\  \\\tt \: Divide \:  6 \:  by  \: 6 \:  to \:  get \:  1. \\  \\  = \boxed{ \boxed{ \bf \:  1}}

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If f(x))= x/2 + 8, what is f(x) when x=10
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10 divided by 2 is 5, 5 + 8 is 13
thus f(10)= 13
hope this helps
6 0
3 years ago
Read 2 more answers
Multiply (2n + 2)(2n – 2) A. 4n 2 – 4 B. 4n 2 – 4n – 4 C. 4n 2 + 2n – 4 D. 4n 2 + 4n – 4
sattari [20]
This system can be a bit tricky unless you write it out:
(2n + 2)(2n - 2) ~ First you have to take one variable and multiply it to each of the other two variables, like:
2n * 2n ~ And:
2n * -2 ~ This gives you:
4n^2 - 4n
Now we do this with the other:
2 * 2n
2 * -2
4n - 4
Now we combine them both while adding like terms:
4n^2 - 4
Therefore your answer is: A. 4n^2 - 4
(This is due to how when having the positive 4n subtracted by the negative it cancels it out. Leaving us with the remaining two terms left.)

I hope this helps, have a great rest of your day! ^ ^
~Ghostgate
7 0
3 years ago
Divide 4.16 into the ratio 3:5<br><br> need answers fast!!!
Over [174]
3:5 =3/5 3/5=4.16/x using cross multiplication, 5(4.15)=3(x) 20.8=3x x=108/15 thus, 4.16÷104/15 =3/5
4 0
3 years ago
Val has 6 yards of fabric she uses 1/3 if it to make a shirt then she uses 3/8 of the fabric that is left to make a shirt for he
Evgen [1.6K]
1/3 of 6=2(4 left)
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5 0
3 years ago
Find the sum: 2 + 9 + 16 + ... + 37
iris [78.8K]

Step-by-step explanation:

Sum of arithmetic terms = n/2 × [2a + (n - 1)×d], where 'a' is the first term, 'd' is the common difference between two numbers, and 'n' is the number of terms.

this is the same as n/2 × (a1 + an), because

an = a1 + (n-1)×d

so, for the series above :

a or a1 = 2

d = 7, as every new term is the previous term plus 7.

for n

37 = a1 + (n-1)×d = 2 + (n-1)×7

and now solve for n

35 = 7n - 7

42 = 7n

n = 6

so, the sum of all terms is

6/2 × (2+37) = 3×39 = 117

7 0
3 years ago
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