The answer is A. u do the othe angle and add it to the fisrt one
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Answer:
4a. ∠V≅∠Y
4b. TU ≅ WX
5. No; no applicable postulate
6. see below
Step-by-step explanation:
<h3>4.</h3>
a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...
∠V≅∠Y
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b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...
TU ≅ WX
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<h3>5.</h3>
The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)
"No, we cannot prove they are congruent because none of the five postulates or theorems can be used."
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<h3>6.</h3>
The first statement/reason is always the list of "given" statements.
1. ∠A≅∠D, AC≅DC . . . . given
2. . . . . vertical angles are congruent
3. . . . . ASA postulate
4. . . . . CPCTC
<span>Equation at the end of step 1 :</span><span> (((x3)•y)-(((3x2•y6)•x)•y))-6y = 0
</span><span>Step 2 :</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
<span> -3x3y7 + x3y - 6y</span> = <span> -y • (3x3y6 - x3 + 6)</span>
Trying to factor a multi variable polynomial :
<span> 3.2 </span> Factoring <span> 3x3y6 - x3 + 6</span>
Try to factor this multi-variable trinomial using trial and error<span>
</span>Factorization fails
<span>Equation at the end of step 3 :</span><span> -y • (3x3y6 - x3 + 6) = 0
</span><span>Step 4 :</span>Theory - Roots of a product :
<span> 4.1 </span> A product of several terms equals zero.<span>
</span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span>
</span>We shall now solve each term = 0 separately<span>
</span>In other words, we are going to solve as many equations as there are terms in the product<span>
</span>Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
<span> 4.2 </span> Solve : -y = 0<span>
</span>Multiply both sides of the equation by (-1) : y = 0
Answer:
58
Step-by-step explanation:
