Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Fail the test.
- Event B: Unfit.
The probability of <u>failing the test</u> is composed by:
- 46% of 37%(are fit).
- 100% of 63%(not fit).
Hence:
The probability of both failing the test and being unfit is:
Hence, the conditional probability is:
0.7873 = 78.73% probability that Mona was justifiably dropped.
A similar problem is given at brainly.com/question/14398287
Answer:
Three times the sum of a number and 2.
Step-by-step explanation:
Sum of a number and 2 = x + 2
3 times = 3 multiplied
Here, we just use the following x values and put them into the equation.
y = - 0.05x + 16
y = -0.5(0) + 16
y = 16
y = - 0.05x + 16
y = -0.5(160) + 16
y = -80 + 16
y = -64
y = - 0.05x + 16
y = -0.5(320) + 16
y = - 160 + 16
y = -144
Now, to set up the table, you could list the x values and the y values.
x values :- 0,160, 320
y values:- 16, -64, -144
Answer:
1. No, This is a repeating decimal. (The line means it goes on forever) 2. No, this is a repeating decimal. 3. Yes. This is a decimal that neither terminates or repeats. 4. Yes. This is a decimal that neither terminates or repeats.
Step-by-step explanation:
Hope this helped!
Answer:
38
Step-by-step explanation:
for this table, we can add up all of the students who chose flying (both the "male" and "female" students)
26 + 12 = 38
So, 38 students chose flying as their superpower.
hope this helps!!
