Answer:
95% confidence interval for the mean number of months is between a lower limit of 6.67 months and an upper limit of 25.73 months.
Step-by-step explanation:
Confidence interval is given as mean +/- margin of error (E)
Data: 5, 15, 12, 22, 27
mean = (5+15+12+22+27)/5 = 81/5 = 16.2 months
sd = sqrt[((5-16.2)^2 + (15-16.2)^2 + (12-16.2)^2 + (22-16.2)^2 + (27-16.2)^2) ÷ 5] = sqrt(58.96) = 7.68 months
n = 5
degree of freedom = n-1 = 5-1 = 4
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (t) corresponding to 4 degrees of freedom and 5% significance level is 2.776
E = t×sd/√n = 2.776×7.68/√5 = 9.53 months
Lower limit of mean = mean - E = 16.2 - 9.53 = 6.67 months
Upper limit of mean = mean + E = 16.2 + 9.53 = 25.73 months
95% confidence interval is (6.67, 25.73)
It's a cubic with a positive x^3 coefficient. The general shape is "/".
It goes to -∞ for large negative x.
It goes to +∞ for large positive x.
The formula of circumference: 兀×diameter
In this case:
3.14×11
=34.54cm
Nearest hundreth = 2 demical places
Therefore, the answer is 34.54cm.
Hope it helps!
The answer is C -5/16 is -0.3 which means -5/16 cant be greater than or less than -0.3 so A and D are wrong and -2/3 is less than -5/16 which leaves us with C!
