PLZZZZ answer 21 points and brainlest <br> pls answer both questions

A group consists of seven men and five women. Three people are selected to attend a conference.

Dima020 [189]

Answer:

a) 220

b) 10

c) 4.55% probability that the selected group will consist of all women.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the people are selected is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

a. In how many ways can three people be selected from this group of twelve?

$C_{12,3} = \frac{12!}{3!(12-3)!} = 220$

b. In how many ways can three women be selected from the five women?

Three women, from a set of 5. So

$C_{5,3} = \frac{5!}{3!(5-3)!} = 10$

c. Find the probability that the selected group will consist of all women.

Desired outcomes:

3 women from a set of 4. So

$D = C_{5,3} = \frac{5!}{3!(5-3)!} = 10$

Total outcomes:

3 people, from a set of 12. So

$T = C_{12,3} = \frac{12!}{3!(12-3)!} = 220$

Probability:

$p = \frac{D}{T} = \frac{10}{220} = 0.0455$

4.55% probability that the selected group will consist of all women.

3 0

3 years ago

Consider this three-digit sequence: 943. Is the first digit the largest or the second digit the smallest, AND, is the third digi

wolverine [178]

The sequence: 9, 4, 3

The largest number in this sequence is 9.
This is because 9 is of greatest value, being farther from 0 than the numbers 3 and 4.

The smallest number in this sequence is 3.
This is because 3 is of least value, being closer to 0 than the numbers 4 and 9.

Knowing this, we can answer the first question- "Is the first digit the largest or the second digit the smallest?"

9 is the first digit in this sequence, and it is the largest.
4 is the second digit in this sequence, and it is not the smallest. 3 is the smallest value in the sequence, but it is not the second digit.

This means that "the first digit is the largest" is the correct answer to the first question.

Even numbers result in integers, numbers without decimals/fractions, when divided by 2.

3 is an odd number, since it does not result in an integer when divided by 2.
3 is the third number in this sequence.

9 is also an odd number for the same reason.
9 is the first number in this sequence.

Knowing this, we can answer the second question- "Is the third digit even or the first digit odd?"

3 is the third digit in the sequence, and it is odd, not even.

9 is the first digit in the sequence, and it is odd.

This means that "the first digit is odd" is the correct answer to the second question.

Answers:
1) The first digit, 9, is the largest digit in the sequence.
2) The first digit, 9, is odd.

Hope this helps!

7 0

3 years ago

Can someone help me on this question please

Nonamiya [84]

Answer:

97

Step-by-step explanation:

Add the sides of the triangle,

44 + 39 = 83

There needs to be 180 degrees in a triangle,

180 - 83 = 97

The remaining side is 97 degrees which is side h

8 0

3 years ago

Read 2 more answers

Find the length to three significant digits of the arc intercepted by a central angle

noname [10]

Answer:41.2in

Step-by-step explanation:

3 0

3 years ago

Consider the probability that no less than 95 out of 152 registered voters will vote in the presidential election. Assume the pr

nikdorinn [45]

Answer:

0.3821 = 38.21% probability that no less than 95 out of 152 registered voters will vote in the presidential election.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

Assume the probability that a given registered voter will vote in the presidential election is 61%.

This means that $p = 0.61$

152 registed voters:

This means that $n = 152$

Mean and Standard deviation:

$\mu = E(X) = 152*0.61 = 92.72$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{152*0.61*0.39} = 6.01$

Probability that no less than 95 out of 152 registered voters will vote in the presidential election.

This is, using continuity correction, $P(X \geq 95 - 0.5) = P(X \geq 94.5)$ , which is 1 subtracted by the pvalue of Z when X = 94.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{94.5 - 92.72}{6.01}$

$Z = 0.3$

$Z = 0.3$ has a pvalue of 0.6179

1 - 0.6179 = 0.3821

0.3821 = 38.21% probability that no less than 95 out of 152 registered voters will vote in the presidential election.

6 0

3 years ago

PLZZZZ answer 21 points and brainlest pls answer both questions