Consider the system of equations. Which is the Best method to use for solving the system? 4x+y=1 2x+y=8

Mathematics

2 answers:

Novay_Z [31]3 years ago

8 0

Answer: It is best solve using elimination method

Step-by-step explanation:

4x + y = 1 --------(1)

2x + y = 8---------(2)

subtract (2) from (1)

2x = -7

divide bothside by 2

2x/2 = -7/2

x= -7/2

we can substitute x = -7/2 in any of the equations.

Lets take equation (1)

4x + y = 1

4(-7/2) + y =1

2(-7) + y = 1

-14 + y = 1

y = 1+14

y =15

Archy [21]3 years ago

5 0

4x + y = 1
-2x - y = -8

2x = -7

x = -7/2

2(-7/2) + y = 8

-7 + y = 8

y= 15

elimination

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Vertex/General Form: y = a(x - h)^2 + k, with (h,k) as the vertex
(x + y)^2 = x^2 + 2xy + y^2
Standard Form: y = ax^2 + bx + c

So before I put the equation into standard form, I'm first going to be putting it into vertex form. Since the vertex appears to be (-1,7), plug that into the vertex form formula:

$y=a(x-(-1))^2+7\\y=a(x+1)^2+7$

Next, we need to solve for a. Looking at this graph, another point that is in this line is the y-intercept (0,5). Plug (0,5) into the x and y placeholders and solve for a as such:

$5=a(0+1)^2+7\\5=a(1)^2+7\\5=a+7\\-2=a$