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Alenkinab [10]
3 years ago
5

The _____ of a story describes the time and location of a story.

Computers and Technology
2 answers:
Crazy boy [7]3 years ago
3 0
The answer is D. Setting
sattari [20]3 years ago
3 0

Answer:

LETTET D= SETTING

Explanation:

the place or type of surroundings where something is positioned or where an event takes place.

Brainliest please

Good Luck

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Why does my Chromebook keep on turning my new tabs into clever tabs?
Alina [70]

Answer:

Ok, so it's not letting me submit a text response, so I'll attach an image of my answer.

Explanation:

6 0
1 year ago
Read 2 more answers
What special case exists when managing linked lists?
tiny-mole [99]

Explanation:

The special case that exists in linked list when we are managing them is when we are dealing with the first element of the list.

When we create a linked list we create a first node separately.

If we delete or add element in front of the first element we have to carefully handle that case.

Hence the special case is when we are dealing with the first element of the list.

6 0
2 years ago
A consumer purchased a grass trimmer from a hardware store. He took it out of the sealed box and assembled it according to the i
Kruka [31]

As to the hardware store, the neighbor will recover because the consumer's failure to recognize the improper assembly doesn't cut off the stores liability.

<h3>What is hardware?</h3>

It should be noted that hardware means the tangible computer components that run the written instructions.

In this case, as to the hardware store, the neighbor will recover because the consumer's failure to recognize the improper assembly doesn't cut off the stores liability.

Learn more about hardware on:

brainly.com/question/24370161

#SPJ12

7 0
1 year ago
Write the following generic method that sorts an ArrayList of Comparable items. The sort method must use the compareTo method.
Inessa05 [86]

Answer:

Explanation:

The following code is written in Java, it prompts the user to enter 10 integers and saves them to an ArrayList. Then it prompts for 5 strings and saves them to another ArrayList. Then, it calls the sort method and adds the lists as parameters. Finally, it prints out both lists completely sorted in ascending order.

import java.util.ArrayList;

import java.util.Scanner;

class Division{

   public static double division(double a, double b) throws Exception {

       if(b == 0)

           //throw new Exception("Invalid number.");

           return (a / b);

       return a / b;

   }

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       ArrayList<Integer> mylist2 = new ArrayList<>();

       for (int x = 0; x < 10; x++) {

           System.out.println("Please Enter a Number: ");

           int number = in.nextInt();

           mylist2.add(number);

       }

       ArrayList<String> mylist = new ArrayList<>();

       for (int x = 0; x < 5; x++) {

           System.out.println("Please Enter a Word: ");

           String word = in.nextLine();

           mylist.add(word);

       }

       sort(mylist);

       sort(mylist2);

       for (String x: mylist) {

           System.out.print(x + ", ");

       }

       System.out.println("");

       for (int x: mylist2) {

           System.out.print(x + ", ");

       }

   }

   public static <E extends Comparable<E>> ArrayList<E> sort(ArrayList<E> list) {

       E temp;

       if (list.size()>1) // check if the number of orders is larger than 1

       {

           for (int x=0; x<list.size(); x++) // bubble sort outer loop

           {

               for (int i=0; i < list.size() - x - 1; i++) {

                   if (list.get(i).compareTo(list.get(i+1)) > 0)

                   {

                       temp = list.get(i);

                       list.set(i,list.get(i+1) );

                       list.set(i+1, temp);

                   }

               }

           }

       }

       return list;

}}

6 0
2 years ago
Convert 192.16.3.1 to a Binary number
jenyasd209 [6]
Converting a decimal number into binary would be:

192/2= 96   remainder=0  
96/2= 48    remainder=0
48/2=24     remainder=0
24/2=12      remainder=0
12/2=6        remainder=0
6/2=3         remainder=0
3/2=1          remainder=1
1/2= 0         remainder=1
The binary number would be: 11 00 00 00

For 16
16/2=8     remainder=0
8/2=4      remainder=0
4/2=2       remainder=0
2/2=1         remainder=0
1/2= 0         remainder=1
The binary would be: 00 01 00 00

For 3
3/2=1       remainder=1
1/2= 0         remainder=1
The binary would be: 00 00 00 11

For 1
1/2= 0         remainder=1
The binary would be: 00 00 00 01

The binary number would be:  
11000000.00010000.00000011.00000001
5 0
3 years ago
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