The
MAX aggregate function.
MAX aggregate function returns the maximum value of an
expression over a group of rows. It can be used as an analytic or an aggregate
function. Aggregate function MAX can operate with Boolean values or can be
converted to a Boolean.
Answer:
In comparison to permanent storage, non-permanent storage, also called volatile memory, is a storage device whose data is lost when its power source is disconnected. Examples of non-permanent storage include CPU cache and RAM.
Explanation:
i just know
Answer:
Insert tab
Explanation:
To use <em>Quick Parts</em>, first go to Insert tab then text group. The icon of <em>Quick Parts</em> is there in the attached picture.You can use the <em>Quick Part Gallery</em> to create, store, and reuse pieces of content, including <em>AutoText</em>, document properties (such as title and author), and fields. These reusable blocks of content are also called <u><em>building blocks</em></u>. <em>AutoText</em> is a common type of building block that stores text and graphics. You can use the <em>Building Blocks Organizer</em> to find or edit a building block
I think there's a typo in the question, otherwise they probably meant a 'she', since the name is Maureen.
Also, the answer is Personal hygiene and grooming.
Answer:
- public static String bothStart(String text1, String text2){
- String s = "";
-
- if(text1.length() > text2.length()) {
- for (int i = 0; i < text2.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }else{
- for (int i = 0; i < text1.length(); i++) {
- if (text1.charAt(i) == text2.charAt(i)) {
- s += text1.charAt(i);
- }else{
- break;
- }
- }
- return s;
- }
- }
Explanation:
Let's start with creating a static method <em>bothStart()</em> with two String type parameters, <em>text1 </em>&<em> text2</em> (Line 1).
<em />
Create a String type variable, <em>s,</em> which will hold the value of the longest substring that both inputs start with the same character (Line 2).
There are two possible situation here: either <em>text1 </em>longer than<em> text2 </em>or vice versa. Hence, we need to create if-else statements to handle these two position conditions (Line 4 & Line 13).
If the length of<em> text1</em> is longer than <em>text2</em>, the for-loop should only traverse both of strings up to the length of the <em>text2 </em>(Line 5). Within the for-loop, we can use<em> charAt()</em> method to extract individual character from the<em> text1</em> & <em>text2 </em>and compare with each other (Line 15). If they are matched, the character should be joined with the string s (Line 16). If not, break the loop.
The program logic from (Line 14 - 20) is similar to the code segment above (Line 4 -12) except for-loop traverse up to the length of <em>text1 .</em>
<em />
At the end, return the s as output (Line 21).
