Answer more questions on every topic you’ve been thought. Answer research questions and questions likely to come out in the exam. Dwell on what you are trying to know more that what you already know. A planner could help as well and the Good God would help you
Answer:
11).
= 90°
12).
= 212°
Step-by-step explanation:
A circle F with AB and CD are the diameters has been given in the figure attached.
11). Since,
= 180°
and 
Therefore,
= 180°
32° +
+ 58° = 180°
= 180° - 90°
= 90°
12. Since,
= 32°
= 
= 180° + 32°
= 212°
Answer:
Lets a,b be elements of G. since G/K is abelian, then there exists k ∈ K such that ab * k = ba (because the class of ab,
is equal to
, thus ab and ba are equal or you can obtain one from the other by multiplying by an element of K.
Since K is a subgroup of H, then k ∈ H. This means that you can obtain ba from ab by multiplying by an element of H, k. Thus,
. Since a and b were generic elements of H, then H/G is abelian.
Answer:
8, 133, 47, 43, 90 (remember to put degree symbols!)
Step-by-step explanation:
i added all of the work and explanations in this files! if you still have questions feel free to comment or message :)