<u>Answer:</u> The Gibbs free energy of the reaction is -445 J/mol.
<u>Explanation:</u>
The chemical equation for the conversion follows:
The expression for of above equation is:
We are given:
[Glyceraldehyde-3-phosphate] = 0.00400 M
[Dihydroxyacetone phosphate] = 0.100 M
Putting values in above equation, we get:
Relation between standard Gibbs free energy and equilibrium constant follows:
where,
= Standard Gibbs free energy = 7.53 kJ/mol = 7530 J/mol (Conversion factor: 1kJ = 1000J)
R = Gas constant =
T = temperature = 298 K
Putting values in above equation, we get:
Hence, the Gibbs free energy of the reaction is -445 J/mol.
Answer:
I don't know 100% but im pretty sure its electrons, if im wrong im really sorry let me know in the comments ill change it
explanation
the nucleus has more weight but its more compact but the electrons are spread apart circling the nucleus and therefor take up more space
Answer:
42.8
Explanation:
Let's consider the following reaction at equilibrium.
CO(g) + 2 H₂(g) ⇌ CH₃OH(g)
The concentration equilibrium constant (Kc) is equal to the product of the concentration of the products raised to their stoichiometric coefficients divided by the product of the concentration of the reactants raised to their stoichiometric coefficients.
The concentration equilibrium constant for this reaction is:
Answer:
Phosphorus
Explanation:
Group V elements- Nitrogen, Phosphorous
period 3- Sodium, Magnesium, Aluminium, Silicon , Phosphorous, Sulphur, Chlorine and Argon
Group v and period 3 is phosphorus
The moles of nitrogen that are in 90.0 g of nitrous oxide N2O is calculated as follows
find the moles of N2O= mass/molar mass
= 90,0g/44g/mol= 2.05 moles
since there is two atoms of Nitrogen the moles of nitrogen = 2 x 2.05 =4.10 moles