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jarptica [38.1K]
3 years ago
11

From a cross between a short-haired guinea pig (hh) and a long-haired guinea pig (Hh), what would be the possible phenotypes of

the offspring?
A. 100% will have long hair.
OB. 75% will have long hair; 25% will have short hair.
OC. 50% will have long hair; 50% will have short hair.
O D. 25% will have long hair; 75% will have short hair.
Chemistry
1 answer:
OleMash [197]3 years ago
5 0

Answer:

C

Explanation:

There will be a two long hair and two short hair

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Is the equation for reaction 1 balanced? Explain your reasoning. If the reaction is not balanced, then state how you would balan
sveticcg [70]

Answer:

Reaction is already balanced

Explanation:

The equation in reaction 1 is given as;

CH3COOH + NaHCO3 --> CO2 + H2O +  Na+   +  CH3COO-

The reaction is already balanced. This is because the umber of atoms of elements in the reactant is equal to that of the products

Carbon

Reactant = 2 + 1 = 3

Product = 2 + 2 = 3

Hydrogen

Reactant = 3 + 1 + 1 = 5

Product = 2 + 3 = 5

Oxygen

Reactant = 2 + 3 = 5

Product = 2 +1 + 2 = 5

Sodium

Reactant = 1

Product = 1

3 0
3 years ago
Which element has chemical properties that are most<br> similar to potassium, And why?
bekas [8.4K]

Answer:

Brainliest pls

Explanation:

The components potassium and sodium have comparable substance properties since they have a similar number of valence electrons

8 0
2 years ago
Which statement best describes the relationship between the giraffe and the tree shown above?
Dominik [7]

Answer

a

Explanation:

the giraffe doesn't need carbon dioxide

8 0
3 years ago
Lead−206 is the end product of 238u decay. one 206pb atom has a mass of 205.974440 amu. (a) calculate the binding energy per nuc
Dovator [93]
The atomic number for Pb is 82
∴ Pb has 82 protons and 206-82 = 14 protons
The actual mass of Pb nuclei is
=(82 × mass of the proton) + (124 × mass of neutron)
=(82× 1.00728) + (124 × 1.008664) amu
= 207.6713 amu
The mass of lead which is given is 205.9744 amu
∴mass defect is
m = 207.6713 - 205.9744 = 1.6969 amu
=1.6969 × 1.66054 × 10⁻²⁷kg
=2.818 × 10⁻²⁷kg
The binding energy is E = mc²
C is the speed of light in vacuum = 2.9979 × 10⁸m/s
∴ E = 2.532 × 10×⁻¹⁰ J/mol
= 2.532 × 10⁻¹⁰ × 6.023 × 10²³ J/mol 
= 1.53811 × 10¹⁴ J/mol

8 0
3 years ago
How hydrogen chloride gas is prepared on labrotary by conc sulpheric acid<br> ​
Citrus2011 [14]

Answer:

It is prepared small amounts of hydrogen cloride for uses in the lab.

It can be  "generated in an HCl generator by dehydrating hydrochloric acid with either sulfuric acid or anhydrous calcium chloride."

4 0
2 years ago
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