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3 years ago

11

Find an equation in slope intercept form of the line that has slope -3 and passes through point (9,4). A.Y=-3x-31 B.Y=31x+3 C.Y=

-3x+31 D.Y=3x+31

1 answer:

Tamiku [17]3 years ago

6 0

Answer:

y=-3x+31

Step-by-step explanation:

y-y1=m(x-x1)

y-4=-3(x-9)

y-4=-3x+27

y=-3x+27+4

y=-3x+31

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In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad

weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

$\angle acd = 60 ^{\circ}$

Therefore, we have

$\angle dcb =90- 60= 30 ^{\circ}$

Now, in triangle bcd, we have

$\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3$

Now, in triangle acb, we have

$tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3= \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15$

Thus, ad is 15 cm.

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