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2 years ago

There are 10 girls in the class. This is three less thank half the number of boys . How many boys are in the class?

Mathematics

2 answers:

Andreas93 [3]2 years ago

5 0

Answer:

there are 6 boys

Step-by-step explanation:

alexdok [17]2 years ago

3 0

If 10 is 3 less, then adding 3 to 10 is 13 and if 13 is half the number of boys then 13 + 13 is 26. I’m not too sure but I think the answer is 26 boys

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3 years ago

Can someone solve and explain this question plz

oee [108]

firstly let's convert the mixed fraction to improper fraction, then hmmm let's see we have two denominators, 5 and 3, and their LCD will simply be 15, so we'll multiply both sides by that LCD to do away with the denominators, let's proceed,

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3 years ago

Please anyone answer me

ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

$A\frac{}{1} = ∫g(x)dx = ∫xdx = \frac{1}{2} {x}^{2} | \frac{2}{0} = 2$

Area 2:

$A\frac{}{2} = ∫(g(x) - f(x))dx$

$= ∫(x - {(x - 2)}^{2} )dx$

$= ∫( - {x}^{2} + 5x - 4)dx$

$= ( - \frac{1}{3}{x}^{3} + \frac{5}{2} {x}^{2} - 4x) | \frac{4}{2}$

$= 2.67 - ( - 0.67) = 3.34$

Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

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3 years ago

Calculating cos-1 ( help is gladly appreciated :) )

Alekssandra [29.7K]

Answer:

$\frac{3\pi}{4}$

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by $\frac{180^\circ}{\pi}$ giving you:

$\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}$ .

We can do this since $\pi \text{ rad }=180^\circ$ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

$\cos^{-1}(x)$ is going to output an angle measurement in $[0,\pi]$ .

So we are looking to solve the following equation in that interval:

$\cos(x)=-\frac{\sqrt{2}}{2}$ .

This happens in the second quadrant on the given interval.

The solution to the equation is $\frac{3\pi}{4}$ .

So we are saying that $\cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2}$ implies $\cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4}$ since $\frac{3\pi}{4} \in [0,\pi]$ .

Answer is $\frac{3\pi}{4}$ .

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2 years ago